Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
this should be an easy problem, but I can't work out the right answer for the life of me:
A couple decides to have children until they get a girl, but agree that they will not have more than 3 children, even if they are all boys. (assume boys and girls are equally likely)
What is a the probability of each outcome?
What is the expected number of children?
What is the expected number of boys?
What is the standard deviation of the number of kids?
 one year ago
 one year ago
this should be an easy problem, but I can't work out the right answer for the life of me: A couple decides to have children until they get a girl, but agree that they will not have more than 3 children, even if they are all boys. (assume boys and girls are equally likely) What is a the probability of each outcome? What is the expected number of children? What is the expected number of boys? What is the standard deviation of the number of kids?
 one year ago
 one year ago

This Question is Closed

ggrreeBest ResponseYou've already chosen the best response.0
from what I understand, the possible outcomes are: 1 girl: (1/2) , 1 boy and then 1 girl (1/2 * 1/2), 2 boys and 1 girl (1/6) or 3 boys (1/6). Clearly something is wrong here because those probabilities do not add up to 1, what am I missing?
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
what are the possible outcomes?
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
oh i see your mistake \[\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}=\frac{1}{8}\]
 one year ago

ggrreeBest ResponseYou've already chosen the best response.0
THANKS! I thought 1/2 * 1/2 * 1/2 was 1/6... wow.
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.