Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

this should be an easy problem, but I can't work out the right answer for the life of me: A couple decides to have children until they get a girl, but agree that they will not have more than 3 children, even if they are all boys. (assume boys and girls are equally likely) What is a the probability of each outcome? What is the expected number of children? What is the expected number of boys? What is the standard deviation of the number of kids?

Collaborative Statistics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
from what I understand, the possible outcomes are: 1 girl: (1/2) , 1 boy and then 1 girl (1/2 * 1/2), 2 boys and 1 girl (1/6) or 3 boys (1/6). Clearly something is wrong here because those probabilities do not add up to 1, what am I missing?
what are the possible outcomes?
oh i see your mistake \[\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}=\frac{1}{8}\]

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

LOL
THANKS! I thought 1/2 * 1/2 * 1/2 was 1/6... wow.
damned arithmetic

Not the answer you are looking for?

Search for more explanations.

Ask your own question