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ggrree
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this should be an easy problem, but I can't work out the right answer for the life of me:
A couple decides to have children until they get a girl, but agree that they will not have more than 3 children, even if they are all boys. (assume boys and girls are equally likely)
What is a the probability of each outcome?
What is the expected number of children?
What is the expected number of boys?
What is the standard deviation of the number of kids?
 one year ago
 one year ago
ggrree Group Title
this should be an easy problem, but I can't work out the right answer for the life of me: A couple decides to have children until they get a girl, but agree that they will not have more than 3 children, even if they are all boys. (assume boys and girls are equally likely) What is a the probability of each outcome? What is the expected number of children? What is the expected number of boys? What is the standard deviation of the number of kids?
 one year ago
 one year ago

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ggrree Group TitleBest ResponseYou've already chosen the best response.0
from what I understand, the possible outcomes are: 1 girl: (1/2) , 1 boy and then 1 girl (1/2 * 1/2), 2 boys and 1 girl (1/6) or 3 boys (1/6). Clearly something is wrong here because those probabilities do not add up to 1, what am I missing?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
what are the possible outcomes?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
oh i see your mistake \[\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}=\frac{1}{8}\]
 one year ago

ggrree Group TitleBest ResponseYou've already chosen the best response.0
THANKS! I thought 1/2 * 1/2 * 1/2 was 1/6... wow.
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
damned arithmetic
 one year ago
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