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(i) show that if the circle x^2 + y^2 + 2gx + 2fy + c = 0 touches the y- axis, then f^2 = c (ii) using the result from part (i) find the equation of the circle which contains the points (2, 3) and (2, -5) and which touches the y axis. i have done part (i) and gotten some of part (ii) but i need help finishing it please

Mathematics
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if you have part I done, the for the second part you have \[x^2+y^2+2gx+2fy+f^2=0\]
i have subed the points in and got the 2 equations but now i'm not sure what to do ?
replace \(x\) by 3, \(y\) by 3 and get an equation in \(f\) and \(g\) repeat with \(x=2\) and \(y=-5\)

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Other answers:

oh i didn't do it, i assumed it would be obvious but maybe not
it just comes up math error ?
let me see if i get it \[4+9+4g+6f+f^2=0\] or \[13+4g+6f+f^2=0\]of \[4g+6f+f^2=-13\] for the first one
still math error for some reason ?
\[4+25+4g-10f+f^2=0\] \[4g-10f+f^2=-29\]
subtract the second equation from the first i get \[16f=16\] and so \(f=1\)
[Math Processing Error] [Math Processing Error] this is what keeps coming up
oh i didn't understand what you mean you mean that is what you see me write refresh your browswer
for some reason your browser was not reading the latex correctly a refresh should work

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