## ForeverRebel Group Title ^4√16M^8 one year ago one year ago

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1. geoffb

$\LARGE \sqrt[4]{16M^8}$ Is that what you're looking at?

2. ForeverRebel

@geoffb yes

3. geoffb

It might be easier if you think of it like: $$\LARGE \sqrt[4]{16 \times M^8}$$ or $$\LARGE \sqrt[4]{16} \times \sqrt[4]{M^8}$$

4. ForeverRebel

@geoffb how do i solve it?

5. geoffb

It can't be solved. There's no equal sign, so you can't say that M "equals" anything. All you can do is reduce it. For example, what is the fourth root of 16?

6. UnkleRhaukus

$16=2^4$ $M^8=(M^2)^4$