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Check my work in stochiochemistry. Did I get the correct result?

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1 Attachment
2 C8H18 + 25 O2 = 16 CO2 + 18 H2O the ratio between C8H18 and CO2 is 2 : 16 moles CO2 formed = 3.5 x 16/ 2= 28

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Oh right! I did that before I corrected the equation.
:) did that help?
Yeah, I have a couple more. If you could check them as well, that would be great.
okay tag me when you post
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It functions based on the original equation.
We shall assume that C8H18 is in excess. First calculate the moles of O2: n(O2) = 300 g / 32.00 g/mol = 9.375 mol Determine the moles H2O using the mole ratio; 18 moles of H2O are formed when 25 moles of O2 react. n(H2O) = (9.375 mol O2)(18 mol H2O / 25 mol O2) = 6.75 mol H2O Multiply the moles of H2O by Avogarod's number to determine # of molecules: (6.75 mol)(6.01x10^23 molecules/mol) = 4.1x10^24 molecules
Last one. Thanks @sara1234 !
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@AccessDenied Could you check this for me?
Could you help me with this last problem? I already did it, but it would be great if you could check it. It's a23.png, and the equation is at the top.
Well, the top as in the top image.
well 2 moles of C8H18 yeilds 16 moles of CO2 1 mole of C8H18 will yeild 8 moles of CO2 therefore 3.5 moles of C8H18 will yeild 8*3.5=28 moles of CO2

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