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Nanoman

  • 2 years ago

Check my work in stochiochemistry. Did I get the correct result?

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  1. Nanoman
    • 2 years ago
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  2. Nanoman
    • 2 years ago
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    @dpaInc @jhonyy9 @Outkast3r09

  3. sara1234
    • 2 years ago
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    2 C8H18 + 25 O2 = 16 CO2 + 18 H2O the ratio between C8H18 and CO2 is 2 : 16 moles CO2 formed = 3.5 x 16/ 2= 28

  4. Nanoman
    • 2 years ago
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    Oh right! I did that before I corrected the equation.

  5. sara1234
    • 2 years ago
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    :) did that help?

  6. Nanoman
    • 2 years ago
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    Yeah, I have a couple more. If you could check them as well, that would be great.

  7. sara1234
    • 2 years ago
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    okay tag me when you post

  8. Nanoman
    • 2 years ago
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  9. Nanoman
    • 2 years ago
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    It functions based on the original equation.

  10. Nanoman
    • 2 years ago
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    @sara1234

  11. sara1234
    • 2 years ago
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    We shall assume that C8H18 is in excess. First calculate the moles of O2: n(O2) = 300 g / 32.00 g/mol = 9.375 mol Determine the moles H2O using the mole ratio; 18 moles of H2O are formed when 25 moles of O2 react. n(H2O) = (9.375 mol O2)(18 mol H2O / 25 mol O2) = 6.75 mol H2O Multiply the moles of H2O by Avogarod's number to determine # of molecules: (6.75 mol)(6.01x10^23 molecules/mol) = 4.1x10^24 molecules

  12. Nanoman
    • 2 years ago
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    Last one. Thanks @sara1234 !

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  13. Nanoman
    • 2 years ago
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    @AccessDenied Could you check this for me?

  14. Nanoman
    • 2 years ago
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    @aaronq @kelly226

  15. Nanoman
    • 2 years ago
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    Could you help me with this last problem? I already did it, but it would be great if you could check it. It's a23.png, and the equation is at the top.

  16. Nanoman
    • 2 years ago
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    Well, the top as in the top image.

  17. Nanoman
    • 2 years ago
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    @ghazi @kymber

  18. ghazi
    • 2 years ago
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    well 2 moles of C8H18 yeilds 16 moles of CO2 1 mole of C8H18 will yeild 8 moles of CO2 therefore 3.5 moles of C8H18 will yeild 8*3.5=28 moles of CO2

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