Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Fredyepr
Group Title
find a cartesian cuestion r=2cos(theta) + 3sin(theta)
 one year ago
 one year ago
Fredyepr Group Title
find a cartesian cuestion r=2cos(theta) + 3sin(theta)
 one year ago
 one year ago

This Question is Closed

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
x/r = cos(theta) y/r = sin(theta) r^2 = x^2 +y^2 have you made those substitutions?
 one year ago

Fredyepr Group TitleBest ResponseYou've already chosen the best response.0
help me you please.... with this
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
make those substitutions... tell me what you get...
 one year ago

Fredyepr Group TitleBest ResponseYou've already chosen the best response.0
r= 2x/r + 3 y/r ...........> r2=2x+2y .. ...............> x2 + y2= 2x + 3y > x22x3y+y2= 0... is it correct¿?
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
you can clean it up a bit by completing the square on both the x and y terms.. eg.: (x^2 2x) = (x^2 2x +1) 1 = (x1)^2 1
 one year ago

Fredyepr Group TitleBest ResponseYou've already chosen the best response.0
what is the best¿?
 one year ago

Fredyepr Group TitleBest ResponseYou've already chosen the best response.0
ok ok thanks .... can you help with other¿?
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
just sub.s in x=rcos(theta), y=rsin(theta)
 one year ago

Fredyepr Group TitleBest ResponseYou've already chosen the best response.0
rcostheta + rsintheta = 8 ¿?
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.