anonymous
  • anonymous
find a cartesian cuestion r=2cos(theta) + 3sin(theta)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
x/r = cos(theta) y/r = sin(theta) r^2 = x^2 +y^2 have you made those substitutions?
anonymous
  • anonymous
help me you please.... with this
anonymous
  • anonymous
make those substitutions... tell me what you get...

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anonymous
  • anonymous
r= 2x/r + 3 y/r ...........> r2=2x+2y .. ...............> x2 + y2= 2x + 3y ------> x2-2x-3y+y2= 0... is it correct¿?
anonymous
  • anonymous
yes
anonymous
  • anonymous
you can clean it up a bit by completing the square on both the x and y terms.. eg.: (x^2 -2x) = (x^2 -2x +1) -1 = (x-1)^2 -1
anonymous
  • anonymous
what is the best¿?
anonymous
  • anonymous
what?
anonymous
  • anonymous
ok ok thanks .... can you help with other¿?
anonymous
  • anonymous
xy=8
anonymous
  • anonymous
just sub.s in x=rcos(theta), y=rsin(theta)
anonymous
  • anonymous
rcostheta + rsintheta = 8 ¿?

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