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Fredyepr

  • 3 years ago

find a cartesian cuestion r=2cos(theta) + 3sin(theta)

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  1. Algebraic!
    • 3 years ago
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    x/r = cos(theta) y/r = sin(theta) r^2 = x^2 +y^2 have you made those substitutions?

  2. Fredyepr
    • 3 years ago
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    help me you please.... with this

  3. Algebraic!
    • 3 years ago
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    make those substitutions... tell me what you get...

  4. Fredyepr
    • 3 years ago
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    r= 2x/r + 3 y/r ...........> r2=2x+2y .. ...............> x2 + y2= 2x + 3y ------> x2-2x-3y+y2= 0... is it correct¿?

  5. Algebraic!
    • 3 years ago
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    yes

  6. Algebraic!
    • 3 years ago
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    you can clean it up a bit by completing the square on both the x and y terms.. eg.: (x^2 -2x) = (x^2 -2x +1) -1 = (x-1)^2 -1

  7. Fredyepr
    • 3 years ago
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    what is the best¿?

  8. Algebraic!
    • 3 years ago
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    what?

  9. Fredyepr
    • 3 years ago
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    ok ok thanks .... can you help with other¿?

  10. Fredyepr
    • 3 years ago
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    xy=8

  11. Algebraic!
    • 3 years ago
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    just sub.s in x=rcos(theta), y=rsin(theta)

  12. Fredyepr
    • 3 years ago
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    rcostheta + rsintheta = 8 ¿?

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