anonymous
  • anonymous
Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Rewrite y = x2 + 14x + 29 in general form. Rewrite y = 3x2 - 24x + 10 in general form.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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slaaibak
  • slaaibak
Is the general form y = a(x-b)2 + c ?
anonymous
  • anonymous
I think it's y=a(x-h)^2+k but im not sure
anonymous
  • anonymous
im just not sure what the variable equal?? @slaaibak

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slaaibak
  • slaaibak
Cool, i'll walk you through it
anonymous
  • anonymous
I just need to know what to plug in. like what does k and h equal??
anonymous
  • anonymous
@slaaibak????????
slaaibak
  • slaaibak
Let's start with the first one: y = x2 + 14x + 29 The key to doing this, is by completing the square for x: y = x2 + 14x + 29 Now add 49 and substract 49, because 49 = (14/2)^2 y = x2 + 14x + 49 - 49 + 29 but, x2 + 14x + 49 = (x+7)^2 so y = (x+7)^2 - 30 so h=-7, k = 30
slaaibak
  • slaaibak
sorry, k = -30
anonymous
  • anonymous
thank you!!!
slaaibak
  • slaaibak
Sorry, I made a mistake haha. y = (x+7)^2 - 20 so h = -7 and k = -20
anonymous
  • anonymous
so is the whole equations supposed to have exact numbers? where do i plug in x^2 14 x and 29?
slaaibak
  • slaaibak
read what I did. It explains everything. You just transform the equation.
anonymous
  • anonymous
im so confused i meant i needed the form with the correct numbers but are you solving for the actual value?
slaaibak
  • slaaibak
I'm not solving anything.... I have the correct form. y = (x+7)^2 - 20
anonymous
  • anonymous
You said h=-7?
anonymous
  • anonymous
^^
slaaibak
  • slaaibak
yes, but I'm just showing how the general form relates to what I got. Nevermind. Just look at the answer: y = (x+7)^2 - 20
anonymous
  • anonymous
could you show me how do the second one? i am still so confused. Sorry, thank you.
slaaibak
  • slaaibak
y = 3x2 - 24x + 10 First factor out the 3: y = 3(x2 - 8x + 10/3) add and subtract: (8/2)^2 = 16 y= 3(x2 - 8x + 16 - 16 + 10/3) Try to go further from here
anonymous
  • anonymous
nvmd thanks anyway

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