## abbie1 2 years ago Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Rewrite y = x2 + 14x + 29 in general form. Rewrite y = 3x2 - 24x + 10 in general form.

1. slaaibak

Is the general form y = a(x-b)2 + c ?

2. abbie1

I think it's y=a(x-h)^2+k but im not sure

3. abbie1

im just not sure what the variable equal?? @slaaibak

4. slaaibak

Cool, i'll walk you through it

5. abbie1

I just need to know what to plug in. like what does k and h equal??

6. abbie1

@slaaibak????????

7. slaaibak

Let's start with the first one: y = x2 + 14x + 29 The key to doing this, is by completing the square for x: y = x2 + 14x + 29 Now add 49 and substract 49, because 49 = (14/2)^2 y = x2 + 14x + 49 - 49 + 29 but, x2 + 14x + 49 = (x+7)^2 so y = (x+7)^2 - 30 so h=-7, k = 30

8. slaaibak

sorry, k = -30

9. abbie1

thank you!!!

10. slaaibak

Sorry, I made a mistake haha. y = (x+7)^2 - 20 so h = -7 and k = -20

11. abbie1

so is the whole equations supposed to have exact numbers? where do i plug in x^2 14 x and 29?

12. slaaibak

read what I did. It explains everything. You just transform the equation.

13. abbie1

im so confused i meant i needed the form with the correct numbers but are you solving for the actual value?

14. slaaibak

I'm not solving anything.... I have the correct form. y = (x+7)^2 - 20

15. abbie1

You said h=-7?

16. abbie1

^^

17. slaaibak

yes, but I'm just showing how the general form relates to what I got. Nevermind. Just look at the answer: y = (x+7)^2 - 20

18. abbie1

could you show me how do the second one? i am still so confused. Sorry, thank you.

19. slaaibak

y = 3x2 - 24x + 10 First factor out the 3: y = 3(x2 - 8x + 10/3) add and subtract: (8/2)^2 = 16 y= 3(x2 - 8x + 16 - 16 + 10/3) Try to go further from here

20. abbie1

nvmd thanks anyway