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dfresenius

  • 3 years ago

Using integrals, how do you find the volume of a equilateral triangle based pyramid with height h? let a equal one side of the triangular base

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  1. slaaibak
    • 3 years ago
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    Ha, good question. Hmm, I think it would be best to define a pyramid in terms of planes, and then using rectangular coordinates to solve

  2. dfresenius
    • 3 years ago
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    |dw:1354836422356:dw|

  3. dfresenius
    • 3 years ago
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    @Algebraic! hey Chief, can you help me out with this volume problem?

  4. dfresenius
    • 3 years ago
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    |dw:1354836727530:dw|

  5. slaaibak
    • 3 years ago
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    http://mathhelpforum.com/calculus/107926-find-volume-described-solid.html

  6. dfresenius
    • 3 years ago
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    How does he get A=root(3)/2 (a^2)

  7. slaaibak
    • 3 years ago
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    |dw:1354837670054:dw|

  8. slaaibak
    • 3 years ago
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    That's using pythagoras. Then the area is just A=bh/2

  9. slaaibak
    • 3 years ago
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    hmm weird, i'd get A=root(3)/4 (a^2)

  10. dfresenius
    • 3 years ago
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    Huh. That is weird. That's what I got also.

  11. slaaibak
    • 3 years ago
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    he made a mistake it seems. \[A = {\sqrt 3 \over 4} \times a^2\]

  12. dfresenius
    • 3 years ago
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    Would that mean this his equation for S(r) is wrong also?

  13. slaaibak
    • 3 years ago
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    I think S(r) is correct.

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