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anonymous
 3 years ago
How do I find the integral from 4 to 4 of (3*sqrt(16x^2)^2 dx ?
I think you have to use usubstitution but I don't entirely understand how that works in this case.
anonymous
 3 years ago
How do I find the integral from 4 to 4 of (3*sqrt(16x^2)^2 dx ? I think you have to use usubstitution but I don't entirely understand how that works in this case.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well the sqrt gets eliminated with the power 2, so...Its a simple integral

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[y=\sqrt{16x^2}\] is the upper half of a circle centered at the origin with radius 4 so \[6\int_{4}^4\sqrt{16x^2}dx\] is 6 times the area of the upper half of a circle with radius 4

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh sorry i didn't see the square at the end if it is really the square root squared, then it is easy enough, although a rather strange way to write it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it is really \[3\int_{4}^4\sqrt{16x^2}^2dx\]?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Assuming it's what sattelite said then this becomes very simple.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1354850130324:dw Then this become easy to integrate.

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.0i think the typo from asker
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