Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Help? Explain? 3x - 9y = 3 6x - 3y = -24

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
These are linear equations what did you want to do with them?
It's a system, I have to solve them but I can't figure out how to do it.
you can solve using elimination: multiply the first equation by 2 to eliminate the x's:\[~~~~~2~(3x-9y=3)~~~~~~\implies~~~~~~~~6x-18y=6\]\[\underline{-~(6x-3y=-24)}~~~~~\implies~~-\underline{(6x-3y=-24)}\]\[~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~0-15y=30\]now solve for y:\[-15y=30\]divide by -15:\[y=-2\] knowing the value of y we could now use substitution to solve for x: pick either of the two equations and plug in the value of y\[3x-9(-2)=3\]distribute:\[3x+18=3\]subtract 18:\[3x=-15\]divide by 3:\[x=-5\] so: \(x=-5\) and \(y=-2\) hope this helps! :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

So much! You helped me understand it better too, thank you so much!
No problem, anytime! :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question