Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


Given f(x)=2-(x^3/6)-x^2. On what interval(s) is the graph of f concave upwards? The derivative is (-x^2/2)-2x but do I set that equal to 0?

  • one year ago
  • one year ago

  • This Question is Closed
  1. aylinalvarez
    Best Response
    You've already chosen the best response.
    Medals 1

    Okay well to find concavity you have to work with the second derivative of the function, so I would take the derivative of (-x^2/2)-2x and then set that equal to 0. Then the values that you get you would put in a sign analysis. Concave up is when the second derivative is increasing.

    • one year ago
  2. Idealist
    Best Response
    You've already chosen the best response.
    Medals 1

    Now I remember. Thank you.

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.