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Given f(x)=2(x^3/6)x^2. On what interval(s) is the graph of f concave upwards?
The derivative is (x^2/2)2x but do I set that equal to 0?
 one year ago
 one year ago
Given f(x)=2(x^3/6)x^2. On what interval(s) is the graph of f concave upwards? The derivative is (x^2/2)2x but do I set that equal to 0?
 one year ago
 one year ago

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aylinalvarezBest ResponseYou've already chosen the best response.1
Okay well to find concavity you have to work with the second derivative of the function, so I would take the derivative of (x^2/2)2x and then set that equal to 0. Then the values that you get you would put in a sign analysis. Concave up is when the second derivative is increasing.
 one year ago

IdealistBest ResponseYou've already chosen the best response.1
Now I remember. Thank you.
 one year ago
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