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Idealist

  • 2 years ago

Given f(x)=2-(x^3/6)-x^2. On what interval(s) is the graph of f concave upwards? The derivative is (-x^2/2)-2x but do I set that equal to 0?

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  1. aylinalvarez
    • 2 years ago
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    Okay well to find concavity you have to work with the second derivative of the function, so I would take the derivative of (-x^2/2)-2x and then set that equal to 0. Then the values that you get you would put in a sign analysis. Concave up is when the second derivative is increasing.

  2. Idealist
    • 2 years ago
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    Now I remember. Thank you.

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