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Idealist
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Given f(x)=2(x^3/6)x^2. On what interval(s) is the graph of f concave upwards?
The derivative is (x^2/2)2x but do I set that equal to 0?
 one year ago
 one year ago
Idealist Group Title
Given f(x)=2(x^3/6)x^2. On what interval(s) is the graph of f concave upwards? The derivative is (x^2/2)2x but do I set that equal to 0?
 one year ago
 one year ago

This Question is Closed

aylinalvarez Group TitleBest ResponseYou've already chosen the best response.1
Okay well to find concavity you have to work with the second derivative of the function, so I would take the derivative of (x^2/2)2x and then set that equal to 0. Then the values that you get you would put in a sign analysis. Concave up is when the second derivative is increasing.
 one year ago

Idealist Group TitleBest ResponseYou've already chosen the best response.1
Now I remember. Thank you.
 one year ago
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