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Idealist
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Given f(x)=2(x^3/6)x^2. On what interval(s) is the graph of f concave upwards?
The derivative is (x^2/2)2x but do I set that equal to 0?
 2 years ago
 2 years ago
Idealist Group Title
Given f(x)=2(x^3/6)x^2. On what interval(s) is the graph of f concave upwards? The derivative is (x^2/2)2x but do I set that equal to 0?
 2 years ago
 2 years ago

This Question is Closed

aylinalvarez Group TitleBest ResponseYou've already chosen the best response.1
Okay well to find concavity you have to work with the second derivative of the function, so I would take the derivative of (x^2/2)2x and then set that equal to 0. Then the values that you get you would put in a sign analysis. Concave up is when the second derivative is increasing.
 2 years ago

Idealist Group TitleBest ResponseYou've already chosen the best response.1
Now I remember. Thank you.
 2 years ago
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