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I guess we must show that\[\frac{f(0)}{|f(0)|}\neq0\]

can't get l'Hospital to yield anything really...

\[\Large f'(x)=|\frac{f(x)-f(0)}{x-c}-f'(c)|<\epsilon\]

this is the epsilon-delta definition of diff. at c..

sorry should be this\[\Large f'(x)=|\frac{f(x)-f(c)}{x-c}-f'(c)|<\epsilon\]

yeah that looks a bit better...

oh, @mahmit2012 is here, he can likely help.

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