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How do you find all the zeros of the function: f(x)=x^4-x^3+2x^2-4x-8

Mathematics
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Factor or graph.
can you show me how to factor this problem

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Other answers:

factored (x-2)*(x+1)*(x^2+4) ^ notice here you have to take negative sqrt of a the number so it is 2 imaginaries. {x = 2}, {x = -1}, {x = 2*I}, {x = -2*I}
isn't x^2+4 prime?
Oh okay http://answers.yahoo.com/question/index?qid=20091115111403AAnQ7Zk I see what you did there :) Gracias!!!!
De nada :D

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