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jennychan12Best ResponseYou've already chosen the best response.0
6(1+cos^2(7t))^3 6(3(1+cos^2(7t))(sin(7t))(7) Simplify.
 one year ago

roselinBest ResponseYou've already chosen the best response.0
how did you get the 3?
 one year ago

jennychan12Best ResponseYou've already chosen the best response.0
for example, 1/x is x^1.
 one year ago

roselinBest ResponseYou've already chosen the best response.0
\[y=1/6(1+\cos ^{2}(7t))^{3}\]
 one year ago

jennychan12Best ResponseYou've already chosen the best response.0
you can rewrite it as 6(1+cos^2(7t))^3 6(3(1+cos^2(7t))(sin(7t))(7) Simplify and rewrite.
 one year ago

roselinBest ResponseYou've already chosen the best response.0
cAN YOU EXPLAIN HOW YOU GOT THAT?
 one year ago

malevolence19Best ResponseYou've already chosen the best response.0
Assuming you have: \[y=\frac{1}{6}(1+\cos^2(7t))^3\] Then you have quite a few chain rules. One from the cos(7t) one from cos^2(7t) and one from (1+cos^2(7t))^3. So lets move from the outside in: \[\dot{y}=\frac{1}{6}(3)(1+\cos^2(7t))^2 \frac{d}{dt}(1+\cos^2(7t))=\frac{1}{6}(3)(1+\cos^2(7t))^2 \frac{d}{dt}\cos^2(7t)\] \[\implies \frac{1}{6}(3)(1+\cos^2(7t))^2\left[(2)(7)\cos(7t)(\sin(7t) \right]\] Then simplify.
 one year ago

malevolence19Best ResponseYou've already chosen the best response.0
You're still isn't right thought. When you take the inner derivative of cos^2(7t) you should get a 2(7)cos(7t)(sin(7t))
 one year ago
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