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roseflight
What is the limit of sin(2x)/(3x) as x approaches 0
Would you like the step by step?
\[\frac{\sin(2x)}{3x}=\frac13\cdot\frac{\sin(2x)}x=\frac23\cdot\frac{\sin(2x)}{2x}\]
Sorry, but I still don't get how that would equal 2/3.
did you know that\[\lim_{x\to0}\frac{\sin x}x=1\]?
Haha I didn't remember that for some reason. Thanks!
how 'bout this then.... \(\large \frac{sin(2x)}{3x}=\frac{2sinxcosx}{3x}=\frac{2}{3}\cdot \frac{sinx}{x}\cdot cosx \)