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mayankdevnani
Group Title
Two adjacent sides of a parallelogram are 51 cm and 37 cm. One of its diagonals is 20 cm, then its area is.....
a) \[412 cm^2\]
b) \[512 cm^2\]
c) \[612 cm^2\]
d) \[712 cm^2\]
 one year ago
 one year ago
mayankdevnani Group Title
Two adjacent sides of a parallelogram are 51 cm and 37 cm. One of its diagonals is 20 cm, then its area is..... a) \[412 cm^2\] b) \[512 cm^2\] c) \[612 cm^2\] d) \[712 cm^2\]
 one year ago
 one year ago

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sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Use herons formula to calculate the area of one half of the parallelogram.
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
dw:1354886905111:dw
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
dw:1354886978203:dw
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
dw:1354887034102:dw
 one year ago

chihiroasleaf Group TitleBest ResponseYou've already chosen the best response.0
yes.., s = 54, then what is the area of the triangle?
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Good going
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
dw:1354887176565:dw
 one year ago

chihiroasleaf Group TitleBest ResponseYou've already chosen the best response.0
yup..., now simplify ...
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
dw:1354887394948:dw
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
now, then multiply it by 2 to get 612 cm^2. so option c is right answer.....right???
 one year ago

chihiroasleaf Group TitleBest ResponseYou've already chosen the best response.0
right... :)
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
right? @chihiroasleaf and @sauravshakya
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
any short method!!!!
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
@hartnn @sirm3d @amistre64 @AravindG @AccessDenied any short method!!!to solve this question!!!
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
@DLS @satellite73 @nubeer plz help me!!!
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
if u were given the coordinates then I would've given u a shorter method
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
no, i am in 9 class its very long method
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
anyways!!! thnx...
 one year ago

scarydoor Group TitleBest ResponseYou've already chosen the best response.0
I may have a way of calculating those coordinates quickly: dw:1354889186448:dw \[x^2+y^2=c^2\\x^2+(ya)^2=b^2\\x^2+y^2+a^22ay=b^2\\c^2+a^22ay=b^2\\y=\frac{b^2c^2a^2}{2a}\\x=\sqrt{\frac{b^2a^2}{2a}}\]
 one year ago

scarydoor Group TitleBest ResponseYou've already chosen the best response.0
So now you know the coordinates of the parallelogram. There is a formula from algebra about how to calculate the area. It involves cross products or inner products or something?
 one year ago

scarydoor Group TitleBest ResponseYou've already chosen the best response.0
http://en.wikipedia.org/wiki/Parallelogram#The_area_on_coordinate_system
 one year ago

scarydoor Group TitleBest ResponseYou've already chosen the best response.0
If you had good memory, you could just memorise the formula for x and y that I derived above. (I think it's right...) Then calculating the area would take about three lines.
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
thnx... @scarydoor
 one year ago

scarydoor Group TitleBest ResponseYou've already chosen the best response.0
actually the formula for x might be slightly off.... but it can be fixed I think.
 one year ago
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