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Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.0
What is this you're doing lol
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
i have taken the Laplace transform of some periodic functions i dont know how to check if i have done it right
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
i have used \[\mathcal L\{f(x)\}=\int\limits_0^\infty f(x)e^{px}\text dx\] \[=\int\limits_0^\tau f(x)e^{px}\text dx+\int\limits_\tau^{2\tau} f(x)e^{px}\text dx+\int\limits_{2\tau}^{3\tau} f(x)e^{px}\text dx+\dots\]\[=(1+e^{p\tau}+e^{2p\tau}+\dots)\int\limits_0^\tau f(z)e^{pz}\text dz\]\[=\frac{1}{1e^{p\tau}}\int\limits_0^\tau f(z)e^{pz}\text dz\]
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
how do you type a document like that is it LaTex ,it looks great csry i cant help with the content but the presentation is fine hw do you create such a presentation
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
i have been using a program called TeXShop
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.0
How sure are you that it converges?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
i dont know
 one year ago

malevolence19 Group TitleBest ResponseYou've already chosen the best response.0
As long as the function grows slower than Me^pt then it converges.
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
ok it converges because the slope is only positive or negative 1 , which is less slope than any exponential
 one year ago

malevolence19 Group TitleBest ResponseYou've already chosen the best response.0
Yeah, I'm not sure of the name of the theorem but I just went over that in one of my classes not too long ago.
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.2
geometric series?
 one year ago
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