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 2 years ago
Two point charges of equal magnitude are
7.5 cm apart. At the midpoint of the line
connecting them, their combined electric field
has magnitude of 45 N/C. Find the magnitude
of the charges.
Pls show me the complete calculation
 2 years ago
Two point charges of equal magnitude are 7.5 cm apart. At the midpoint of the line connecting them, their combined electric field has magnitude of 45 N/C. Find the magnitude of the charges. Pls show me the complete calculation

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Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1first tell me what is the formula to calculate electric field due to a point charge?

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1ok.. good.. tell me.. do you think the charges should be of same nature or opposite nature?? or both possible? doesn't matter?

shaqadry
 2 years ago
Best ResponseYou've already chosen the best response.0i think it has the same nature since the magnitude of electric field is high

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1ok.. if the charges are of same nature.. then think the direction of the electric field due to each charge at the mid point? will they be same direction or opposite direction?

shaqadry
 2 years ago
Best ResponseYou've already chosen the best response.0i think same direction

shaqadry
 2 years ago
Best ResponseYou've already chosen the best response.0i dont know what happens at the center :/ the radius is halved i guess?

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1how is that?? the direction of electric field due to a positive charge is always AWAY from the charge!!

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1now.. Ea + Eb = the required answer.. !!... Ea you can find.. Eb you can find.. add them equate to required answer.. get Q

shaqadry
 2 years ago
Best ResponseYou've already chosen the best response.0i did try that but i cant seem to get the correct anwers. the answer is 3.5 x 10^12

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1No now.. the net force will add up and = 45 N/C

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1\[2Q/4\pi \epsilon r ^{2}= 45\]

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1r is .075/ 2 cause the mid point is half the distnace

shaqadry
 2 years ago
Best ResponseYou've already chosen the best response.0i got the answer! thank you very much :)

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.1your welcome!.. i could have given the answer before.. but i wanted you to think and get it :P

shaqadry
 2 years ago
Best ResponseYou've already chosen the best response.0i know it helps a lot! so thank you!
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