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shaqadry
Group Title
Two point charges of equal magnitude are
7.5 cm apart. At the midpoint of the line
connecting them, their combined electric field
has magnitude of 45 N/C. Find the magnitude
of the charges.
Pls show me the complete calculation
 one year ago
 one year ago
shaqadry Group Title
Two point charges of equal magnitude are 7.5 cm apart. At the midpoint of the line connecting them, their combined electric field has magnitude of 45 N/C. Find the magnitude of the charges. Pls show me the complete calculation
 one year ago
 one year ago

This Question is Closed

Mashy Group TitleBest ResponseYou've already chosen the best response.1
first tell me what is the formula to calculate electric field due to a point charge?
 one year ago

shaqadry Group TitleBest ResponseYou've already chosen the best response.0
E=F/q=kq/r^2
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
ok.. good.. tell me.. do you think the charges should be of same nature or opposite nature?? or both possible? doesn't matter?
 one year ago

shaqadry Group TitleBest ResponseYou've already chosen the best response.0
i think it has the same nature since the magnitude of electric field is high
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
ok.. if the charges are of same nature.. then think the direction of the electric field due to each charge at the mid point? will they be same direction or opposite direction?
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
dw:1354890053415:dw
 one year ago

shaqadry Group TitleBest ResponseYou've already chosen the best response.0
i think same direction
 one year ago

shaqadry Group TitleBest ResponseYou've already chosen the best response.0
i dont know what happens at the center :/ the radius is halved i guess?
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
how is that?? the direction of electric field due to a positive charge is always AWAY from the charge!!
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
dw:1354890336186:dw
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
dw:1354890474542:dw
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
now.. Ea + Eb = the required answer.. !!... Ea you can find.. Eb you can find.. add them equate to required answer.. get Q
 one year ago

shaqadry Group TitleBest ResponseYou've already chosen the best response.0
the net force is 0?
 one year ago

shaqadry Group TitleBest ResponseYou've already chosen the best response.0
i did try that but i cant seem to get the correct anwers. the answer is 3.5 x 10^12
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
No now.. the net force will add up and = 45 N/C
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
\[2Q/4\pi \epsilon r ^{2}= 45\]
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
r is .075/ 2 cause the mid point is half the distnace
 one year ago

shaqadry Group TitleBest ResponseYou've already chosen the best response.0
i got the answer! thank you very much :)
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
your welcome!.. i could have given the answer before.. but i wanted you to think and get it :P
 one year ago

shaqadry Group TitleBest ResponseYou've already chosen the best response.0
i know it helps a lot! so thank you!
 one year ago
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