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minnie123
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Change 0.1313... to a common fraction.
 one year ago
 one year ago
minnie123 Group Title
***Help Wanted*** ***Medal and Fan Earned*** Change 0.1313... to a common fraction.
 one year ago
 one year ago

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RadEn Group TitleBest ResponseYou've already chosen the best response.2
first, let x = 0.13131313.... now multiply by 100 to both sides, what u get
 one year ago

minnie123 Group TitleBest ResponseYou've already chosen the best response.0
100x=13.131313
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.0
Here is an example http://www.khanacademy.org/math/arithmetic/decimals/v/covertingrepeatingdecimalstofractions1
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.2
ok, good... so, if given 2 equations : 100x = 13.13131313.... and x = 0.13131313 .... subtract of both, 1st equation  2nd equation, what u get
 one year ago

minnie123 Group TitleBest ResponseYou've already chosen the best response.0
can you rephrase what you want me to subtract please?
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.2
it means, left side  left side = right side  right side 100x  x = 13.131313...  0.13131313... , right ?
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.2
well, i will figure out dw:1354893841737:dw
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
RadEn has a great proof; after about a hundred of these you see a pattern 0.abc... repeats abc then; abc/999 is the fraction the number of 9s in the denominator is the number of positions that are repeated
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.2
simplied again... 99x = 13 solve for x, just dividing by 99 to both sides u will get the answr
 one year ago

minnie123 Group TitleBest ResponseYou've already chosen the best response.0
13/99 ... thanks for all of your help... i would have responded sooner but my internet is crappy...
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.2
correct, good finishing :)
 one year ago
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