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anonymous
 3 years ago
A sphere is increasing in volume at the rate 3pi cm^3/s. At what rate is its radius changing when the radius is 1/2 cm?
anonymous
 3 years ago
A sphere is increasing in volume at the rate 3pi cm^3/s. At what rate is its radius changing when the radius is 1/2 cm?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0V=4/3 pi r^3 dV/dt=d(4/3pi r^3)/dt

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Now, use chain rule to find dr/dt

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dr/dt = 1/(4pi r^2) * (dV/dt)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Substitute 1/2 in for r?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dr/dt = 1/(4pi*((1/2)^2))*3pi cm^3/s = 3 cm^3/s Thank you!! :)
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