A community for students.
Here's the question you clicked on:
← 55 members online
 0 viewing
anonymous
 4 years ago
A sphere is increasing in volume at the rate 3pi cm^3/s. At what rate is its radius changing when the radius is 1/2 cm?
anonymous
 4 years ago
A sphere is increasing in volume at the rate 3pi cm^3/s. At what rate is its radius changing when the radius is 1/2 cm?

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0V=4/3 pi r^3 dV/dt=d(4/3pi r^3)/dt

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now, use chain rule to find dr/dt

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dr/dt = 1/(4pi r^2) * (dV/dt)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Substitute 1/2 in for r?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dr/dt = 1/(4pi*((1/2)^2))*3pi cm^3/s = 3 cm^3/s Thank you!! :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.