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Bladerunner1122 Group Title

A sphere is increasing in volume at the rate 3pi cm^3/s. At what rate is its radius changing when the radius is 1/2 cm?

  • one year ago
  • one year ago

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  1. sauravshakya Group Title
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    V=4/3 pi r^3 dV/dt=d(4/3pi r^3)/dt

    • one year ago
  2. sauravshakya Group Title
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    Now, use chain rule to find dr/dt

    • one year ago
  3. sauravshakya Group Title
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    can u?

    • one year ago
  4. Bladerunner1122 Group Title
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    dr/dt = 1/(4pi r^2) * (dV/dt)

    • one year ago
  5. Bladerunner1122 Group Title
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    Substitute 1/2 in for r?

    • one year ago
  6. sauravshakya Group Title
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    yes

    • one year ago
  7. sauravshakya Group Title
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    and dV/dt=3pi cm^3/s

    • one year ago
  8. Bladerunner1122 Group Title
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    dr/dt = 1/(4pi*((1/2)^2))*3pi cm^3/s = 3 cm^3/s Thank you!! :)

    • one year ago
  9. sauravshakya Group Title
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    welcome

    • one year ago
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