anonymous
  • anonymous
can someone check my answer? find the vertex, just not sure about the negatives
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
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slaaibak
  • slaaibak
correct
slaaibak
  • slaaibak
usually, to check which value is the x-coordinate of the vertex, just check what value of x will make the bracket zero. in this case it's (-4 + 4)^2 - 33 so x-coordinate = -4

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slaaibak
  • slaaibak
oh, sorry, I never saw the equation was x = y^2 + 8y - 17 it's gonna be a bit different now, I'll post the solution now
campbell_st
  • campbell_st
the vertex is at (h, k) and the general form is y=(x -h )^2 + k but since the parabola x = y^2 + 8y - 17 |dw:1354919627767:dw|
anonymous
  • anonymous
yeah, well I have all the steps I'm just confused with the negatives
slaaibak
  • slaaibak
yeah, what cambpell said. so it will be (-33,-4)
campbell_st
  • campbell_st
no the parabola is concave right.... its x = y^2 + 8x - 17
campbell_st
  • campbell_st
the methodology is correct... its problem was identifying the type of parabola you have...
anonymous
  • anonymous
let me show u my steps ill upload a pic
anonymous
  • anonymous
I only need the vertex, but i dont have to graph it... wait a sec please
campbell_st
  • campbell_st
I've seen your method.... but the parabola is not the traditional concave up parabola...
anonymous
  • anonymous
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anonymous
  • anonymous
so it would be (-4,-33) ?
anonymous
  • anonymous
yes, @slaaibak but its (h,k) so (-4,-33) right?
campbell_st
  • campbell_st
the methodolgy is correct... here is the graph attached the error is in the general form that you have used. for parabola that are in the form x = ay^2 + by + c the vertex form is x = (y - k)^2 + h
anonymous
  • anonymous
ok got it! thanks a lot :)

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