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cos00155079
 3 years ago
can someone check my answer? find the vertex, just not sure about the negatives
cos00155079
 3 years ago
can someone check my answer? find the vertex, just not sure about the negatives

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slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1usually, to check which value is the xcoordinate of the vertex, just check what value of x will make the bracket zero. in this case it's (4 + 4)^2  33 so xcoordinate = 4

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1oh, sorry, I never saw the equation was x = y^2 + 8y  17 it's gonna be a bit different now, I'll post the solution now

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.1the vertex is at (h, k) and the general form is y=(x h )^2 + k but since the parabola x = y^2 + 8y  17 dw:1354919627767:dw

cos00155079
 3 years ago
Best ResponseYou've already chosen the best response.0yeah, well I have all the steps I'm just confused with the negatives

slaaibak
 3 years ago
Best ResponseYou've already chosen the best response.1yeah, what cambpell said. so it will be (33,4)

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.1no the parabola is concave right.... its x = y^2 + 8x  17

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.1the methodology is correct... its problem was identifying the type of parabola you have...

cos00155079
 3 years ago
Best ResponseYou've already chosen the best response.0let me show u my steps ill upload a pic

cos00155079
 3 years ago
Best ResponseYou've already chosen the best response.0I only need the vertex, but i dont have to graph it... wait a sec please

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.1I've seen your method.... but the parabola is not the traditional concave up parabola...

cos00155079
 3 years ago
Best ResponseYou've already chosen the best response.0so it would be (4,33) ?

cos00155079
 3 years ago
Best ResponseYou've already chosen the best response.0yes, @slaaibak but its (h,k) so (4,33) right?

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.1the methodolgy is correct... here is the graph attached the error is in the general form that you have used. for parabola that are in the form x = ay^2 + by + c the vertex form is x = (y  k)^2 + h

cos00155079
 3 years ago
Best ResponseYou've already chosen the best response.0ok got it! thanks a lot :)
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