Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

cos00155079

  • 2 years ago

can someone check my answer? find the vertex, just not sure about the negatives

  • This Question is Closed
  1. cos00155079
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  2. slaaibak
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    correct

  3. slaaibak
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    usually, to check which value is the x-coordinate of the vertex, just check what value of x will make the bracket zero. in this case it's (-4 + 4)^2 - 33 so x-coordinate = -4

  4. slaaibak
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    oh, sorry, I never saw the equation was x = y^2 + 8y - 17 it's gonna be a bit different now, I'll post the solution now

  5. campbell_st
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    the vertex is at (h, k) and the general form is y=(x -h )^2 + k but since the parabola x = y^2 + 8y - 17 |dw:1354919627767:dw|

  6. cos00155079
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah, well I have all the steps I'm just confused with the negatives

  7. slaaibak
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yeah, what cambpell said. so it will be (-33,-4)

  8. campbell_st
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    no the parabola is concave right.... its x = y^2 + 8x - 17

  9. campbell_st
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    the methodology is correct... its problem was identifying the type of parabola you have...

  10. cos00155079
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    let me show u my steps ill upload a pic

  11. cos00155079
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I only need the vertex, but i dont have to graph it... wait a sec please

  12. campbell_st
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I've seen your method.... but the parabola is not the traditional concave up parabola...

  13. cos00155079
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  14. cos00155079
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so it would be (-4,-33) ?

  15. cos00155079
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes, @slaaibak but its (h,k) so (-4,-33) right?

  16. campbell_st
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    the methodolgy is correct... here is the graph attached the error is in the general form that you have used. for parabola that are in the form x = ay^2 + by + c the vertex form is x = (y - k)^2 + h

  17. cos00155079
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok got it! thanks a lot :)

  18. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.