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justinfung

Are there any inflection points for f(x)=x^2/((x^2)-4)?

  • one year ago
  • one year ago

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  1. mukushla
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    derivate it twice and set the it equal to zero...in other words solve this equation\[f''(x)=0\]

    • one year ago
  2. justinfung
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    I got 32+24x^2 as the numerator

    • one year ago
  3. mukushla
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    let me check it

    • one year ago
  4. mukushla
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    quite right :) and that results in ????

    • one year ago
  5. justinfung
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    nothing?

    • one year ago
  6. mukushla
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    is there any solution for\[32+24x^2=0\]???

    • one year ago
  7. justinfung
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    I don't think so? o.O

    • one year ago
  8. mukushla
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    it gives \[x^2=-\frac{4}{3}\] which is not a true statement for real numbers

    • one year ago
  9. justinfung
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    So no inflection?

    • one year ago
  10. mukushla
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    yes...no inflection point

    • one year ago
  11. justinfung
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    hm...ok thanks :)

    • one year ago
  12. mukushla
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    yw

    • one year ago
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