justinfung
Are there any inflection points for f(x)=x^2/((x^2)4)?



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mukushla
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derivate it twice and set the it equal to zero...in other words solve this equation\[f''(x)=0\]

justinfung
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I got 32+24x^2 as the numerator

mukushla
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let me check it

mukushla
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quite right :) and that results in ????

justinfung
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nothing?

mukushla
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is there any solution for\[32+24x^2=0\]???

justinfung
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I don't think so? o.O

mukushla
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it gives \[x^2=\frac{4}{3}\] which is not a true statement for real numbers

justinfung
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So no inflection?

mukushla
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yes...no inflection point

justinfung
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hm...ok thanks :)

mukushla
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yw