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justinfung

  • 2 years ago

Are there any inflection points for f(x)=x^2/((x^2)-4)?

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  1. mukushla
    • 2 years ago
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    derivate it twice and set the it equal to zero...in other words solve this equation\[f''(x)=0\]

  2. justinfung
    • 2 years ago
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    I got 32+24x^2 as the numerator

  3. mukushla
    • 2 years ago
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    let me check it

  4. mukushla
    • 2 years ago
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    quite right :) and that results in ????

  5. justinfung
    • 2 years ago
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    nothing?

  6. mukushla
    • 2 years ago
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    is there any solution for\[32+24x^2=0\]???

  7. justinfung
    • 2 years ago
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    I don't think so? o.O

  8. mukushla
    • 2 years ago
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    it gives \[x^2=-\frac{4}{3}\] which is not a true statement for real numbers

  9. justinfung
    • 2 years ago
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    So no inflection?

  10. mukushla
    • 2 years ago
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    yes...no inflection point

  11. justinfung
    • 2 years ago
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    hm...ok thanks :)

  12. mukushla
    • 2 years ago
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    yw

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