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anonymous
 4 years ago
Are there any inflection points for f(x)=x^2/((x^2)4)?
anonymous
 4 years ago
Are there any inflection points for f(x)=x^2/((x^2)4)?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0derivate it twice and set the it equal to zero...in other words solve this equation\[f''(x)=0\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I got 32+24x^2 as the numerator

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0quite right :) and that results in ????

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is there any solution for\[32+24x^2=0\]???

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I don't think so? o.O

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it gives \[x^2=\frac{4}{3}\] which is not a true statement for real numbers

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes...no inflection point
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