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la

  • 2 years ago

Hiram raises earthworms. In a square of compost 4 ft by 4 ft, he can have 1,000 earthworms. How many earthworms can he have if his square of compost has a side length that is 7 times longer? How do i solve this!?

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  1. cwrw238
    • 2 years ago
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    the ratios of the areas of small to larger is the ratio of the squares of the sides so as new side is 4 * 5 = 20 ft ratio of their areas is 4^2 : 20^2 = 16 : 400 or 1 : 25

  2. cwrw238
    • 2 years ago
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    so the area is 25 times larger and now you just multiply ...

  3. la
    • 2 years ago
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    THANX:) but multiply what though?

  4. cwrw238
    • 2 years ago
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    1000 by 25

  5. la
    • 2 years ago
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    but that is not one of the answer choices...the answerchoices are a7000 b28,000 c196,000 d49,000

  6. cwrw238
    • 2 years ago
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    lets do it another way area of small square = 4*4 = 16 sq ft the side of big square is 5 times longer that smaller so its 4*5 = 20 ft and its area is 20*20 = 400 sq ft so its 400 / 16 = 25 times bigger number of earthworms = 25 * 1000 = 25,000

  7. cwrw238
    • 2 years ago
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    either the answers are all wrong or maybe you've got the question wrong

  8. la
    • 2 years ago
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    IM SOO SORRRY i had the question wrong lol its 7 instead of 5 Sorry

  9. cwrw238
    • 2 years ago
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    small area = 4*4 = 16 large area = (4*7)^2 = 28^2 so ratio is 28* 28 / 16 use your calculator to find this and then multiply by 1000

  10. la
    • 2 years ago
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    so 1000 x 28 ?

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