Hiram raises earthworms. In a square of compost 4 ft by 4 ft, he can have 1,000 earthworms. How many earthworms can he have if his square of compost has a side length that is 7 times longer? How do i solve this!?
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
the ratios of the areas of small to larger is the ratio of the squares of the sides
so as new side is 4 * 5 = 20 ft
ratio of their areas is 4^2 : 20^2 = 16 : 400 or 1 : 25
so the area is 25 times larger
and now you just multiply ...
Not the answer you are looking for? Search for more explanations.
1000 by 25
but that is not one of the answer choices...the answerchoices are a7000 b28,000 c196,000 d49,000
lets do it another way
area of small square = 4*4 = 16 sq ft
the side of big square is 5 times longer that smaller so its 4*5 = 20 ft
and its area is 20*20 = 400 sq ft
so its 400 / 16 = 25 times bigger
number of earthworms = 25 * 1000 = 25,000
either the answers are all wrong or maybe you've got the question wrong
IM SOO SORRRY i had the question wrong lol its 7 instead of 5 Sorry
small area = 4*4 = 16
large area = (4*7)^2 = 28^2
so ratio is 28* 28 / 16
use your calculator to find this
and then multiply by 1000