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could someone give me a refresher on what to do with somthing like this
\[\sin\left( 2\sin^{1}\left( \frac{1}{2}\right)\right)\]
 one year ago
 one year ago
could someone give me a refresher on what to do with somthing like this \[\sin\left( 2\sin^{1}\left( \frac{1}{2}\right)\right)\]
 one year ago
 one year ago

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ChlorophyllBest ResponseYou've already chosen the best response.1
Start from inside out: 1/2 = sin 30° > 2arcsin1/2 = 2 * 30 = ... => sin (.. ) = ...
 one year ago

richywBest ResponseYou've already chosen the best response.0
thanks, I made a typo though. I meant to say \[\sin\left( 2\sin^{1}\left( \frac{x}{2}\right)\right)\]
 one year ago

richywBest ResponseYou've already chosen the best response.0
\[y=\sin\left( 2\sin^{1}\left( \frac{x}{2}\right)\right)\]\[\sin^{1}y=2\sin^{1}\left(\frac{x}{2}\right)\]
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
sin2(theta) = sin(theta)*cos(theta)
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.1
Use the half angle formula: sin2a = 2 sina cosa with a = arcsin (x/2)
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
dw:1354928836731:dw
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
so x/2 * (sqrt(4x^2))/2
 one year ago

richywBest ResponseYou've already chosen the best response.0
thanks! totally forgot how useful those triangle diagrams are!
 one year ago
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