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richyw
 4 years ago
could someone give me a refresher on what to do with somthing like this
\[\sin\left( 2\sin^{1}\left( \frac{1}{2}\right)\right)\]
richyw
 4 years ago
could someone give me a refresher on what to do with somthing like this \[\sin\left( 2\sin^{1}\left( \frac{1}{2}\right)\right)\]

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Start from inside out: 1/2 = sin 30° > 2arcsin1/2 = 2 * 30 = ... => sin (.. ) = ...

richyw
 4 years ago
Best ResponseYou've already chosen the best response.0thanks, I made a typo though. I meant to say \[\sin\left( 2\sin^{1}\left( \frac{x}{2}\right)\right)\]

richyw
 4 years ago
Best ResponseYou've already chosen the best response.0\[y=\sin\left( 2\sin^{1}\left( \frac{x}{2}\right)\right)\]\[\sin^{1}y=2\sin^{1}\left(\frac{x}{2}\right)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sin2(theta) = sin(theta)*cos(theta)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Use the half angle formula: sin2a = 2 sina cosa with a = arcsin (x/2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1354928836731:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so x/2 * (sqrt(4x^2))/2

richyw
 4 years ago
Best ResponseYou've already chosen the best response.0thanks! totally forgot how useful those triangle diagrams are!
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