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im having trouble integrating the double iterated integral R= [0,3] X [0,rad(9-y^2)] and the function inside the integral is "y dy dx"

Mathematics
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\[\int\limits_{0}^{3}\int\limits_{0}^{\sqrt{9-7^{2}}} y dy dx\] thats the integral
something's not right with either your limits or your order of integration...
sorry your right.... its y dx dy

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Other answers:

if you're integrating in 'dy' .. your limits will be functions of x
ok
that works...
integral of ydx is yx +C
ive tried u sub...and integration by parts. but i just cant get the answer....
still something weird about it though... shouldn't be written like that...
the problem just says.... evaluate the iterated integral
k
they're writing it weird to try and throw you off I guess...
anyway... plug in the limits on 'x' ... ( 0 ... srt(9-y^2) ) and then evaluate with respect to dy
but then what? dont we need to simplifly
so (y*sqrt(9-y^2) + C) dy
you can use u sub.s ...
9-y^2 = u -2y dy = du y dy = -du/2
yes but then we need to plug in 3 into \[\sqrt{9-3^{2}}\] wich equals 0 in the rad
so?
ends up canceling everything out.... and the answer is supposed to be 3
...
lower limit?
is 0
omg....
ive done this problem like no lie 10 times and i never pluged in the lower limit = 0 giving me the right answer 9
thank you so much for letting me realize this. how to i give a medal??
click 'best response'

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