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la
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Hiram raises earthworms. In a square of compost 4 ft by 4 ft, he can have 1,000 earthworms. How many earthworms can he have if his square of compost has a side length that is 7 times longer? Help please?
 one year ago
 one year ago
la Group Title
Hiram raises earthworms. In a square of compost 4 ft by 4 ft, he can have 1,000 earthworms. How many earthworms can he have if his square of compost has a side length that is 7 times longer? Help please?
 one year ago
 one year ago

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josh(theta) Group TitleBest ResponseYou've already chosen the best response.0
hiram has a lot of worms 4 x 4 = 1,000 4 x 4(7) =7 boxes at 4x4 or 7,000 worms
 one year ago

josh(theta) Group TitleBest ResponseYou've already chosen the best response.0
above, 4 x 4 means 4 by 4, not 4 * 4, that looks confusing.
 one year ago

la Group TitleBest ResponseYou've already chosen the best response.0
answer choices are 49,000 or 196,000
 one year ago

Jithinkv Group TitleBest ResponseYou've already chosen the best response.0
if the side length become 7 times ,then it should be 4(7) x 4(7)
 one year ago

Jithinkv Group TitleBest ResponseYou've already chosen the best response.0
=49(1000)=49000
 one year ago

josh(theta) Group TitleBest ResponseYou've already chosen the best response.0
if both side lengths are increased by 7, he would have 7*7 more worms, or 49,00
 one year ago

Jithinkv Group TitleBest ResponseYou've already chosen the best response.0
no of earthworm is proportional to the area of the plot 1000 ~ 4*4 (let ~ stand for proportional) now sides are 7 times longer (7*4)*(7*4) =7*7*(4*4) we already know (4*4)~1000 so =7*7*1000=49000
 one year ago

Jithinkv Group TitleBest ResponseYou've already chosen the best response.0
did u get that ?
 one year ago

la Group TitleBest ResponseYou've already chosen the best response.0
yes thanx!:) so much
 one year ago
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