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la Group Title

Hiram raises earthworms. In a square of compost 4 ft by 4 ft, he can have 1,000 earthworms. How many earthworms can he have if his square of compost has a side length that is 7 times longer? Help please?

  • one year ago
  • one year ago

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  1. josh(theta) Group Title
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    hiram has a lot of worms 4 x 4 = 1,000 4 x 4(7) =7 boxes at 4x4 or 7,000 worms

    • one year ago
  2. josh(theta) Group Title
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    above, 4 x 4 means 4 by 4, not 4 * 4, that looks confusing.

    • one year ago
  3. la Group Title
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    answer choices are 49,000 or 196,000

    • one year ago
  4. Jithinkv Group Title
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    if the side length become 7 times ,then it should be 4(7) x 4(7)

    • one year ago
  5. Jithinkv Group Title
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    =49(1000)=49000

    • one year ago
  6. josh(theta) Group Title
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    if both side lengths are increased by 7, he would have 7*7 more worms, or 49,00

    • one year ago
  7. la Group Title
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    im confused :(

    • one year ago
  8. Jithinkv Group Title
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    no of earthworm is proportional to the area of the plot 1000 ~ 4*4 (let ~ stand for proportional) now sides are 7 times longer (7*4)*(7*4) =7*7*(4*4) we already know (4*4)~1000 so =7*7*1000=49000

    • one year ago
  9. Jithinkv Group Title
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    did u get that ?

    • one year ago
  10. la Group Title
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    yes thanx!:) so much

    • one year ago
  11. Jithinkv Group Title
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    :)

    • one year ago
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