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la

  • 3 years ago

Hiram raises earthworms. In a square of compost 4 ft by 4 ft, he can have 1,000 earthworms. How many earthworms can he have if his square of compost has a side length that is 7 times longer? Help please?

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  1. josh(theta)
    • 3 years ago
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    hiram has a lot of worms 4 x 4 = 1,000 4 x 4(7) =7 boxes at 4x4 or 7,000 worms

  2. josh(theta)
    • 3 years ago
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    above, 4 x 4 means 4 by 4, not 4 * 4, that looks confusing.

  3. la
    • 3 years ago
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    answer choices are 49,000 or 196,000

  4. Jithinkv
    • 3 years ago
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    if the side length become 7 times ,then it should be 4(7) x 4(7)

  5. Jithinkv
    • 3 years ago
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    =49(1000)=49000

  6. josh(theta)
    • 3 years ago
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    if both side lengths are increased by 7, he would have 7*7 more worms, or 49,00

  7. la
    • 3 years ago
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    im confused :(

  8. Jithinkv
    • 3 years ago
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    no of earthworm is proportional to the area of the plot 1000 ~ 4*4 (let ~ stand for proportional) now sides are 7 times longer (7*4)*(7*4) =7*7*(4*4) we already know (4*4)~1000 so =7*7*1000=49000

  9. Jithinkv
    • 3 years ago
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    did u get that ?

  10. la
    • 3 years ago
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    yes thanx!:) so much

  11. Jithinkv
    • 3 years ago
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    :)

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