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Jusaquikie
Group Title
a chemist runs the balanced chemical reaction shown below by mixing 6.18g o Ca3P2 with 9.49g of H2O, how much of PH3 will be formed asuming 100% yield?
 one year ago
 one year ago
Jusaquikie Group Title
a chemist runs the balanced chemical reaction shown below by mixing 6.18g o Ca3P2 with 9.49g of H2O, how much of PH3 will be formed asuming 100% yield?
 one year ago
 one year ago

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Jusaquikie Group TitleBest ResponseYou've already chosen the best response.0
\[Ca _{3}P _{2}(s)+6H _{2}O(l)\rightarrow 3 Ca(OH)_{s}(s)+2 PH _{3}(g)\]
 one year ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.1
http://openstudy.com/study#/updates/50c27afae4b066f22e104a93 I explain limiting reagent
 one year ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.1
If there is a 100% yield you would just be determining the theoretical yield, scroll down to the bottom post of that question
 one year ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.0
i took the grams of Ca3P2/MM and H20 and got the limiting agent as the CaP2 and that is a 1:1 ratio with the 2PH3
 one year ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.0
once i figure out the ratio is 1:1 then i take the moles of Ca3P2 then multiply by the MM of PH3 to get the grams right?
 one year ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.1
The ratio between Ca3P2 and PH3 isn't 1:1
 one year ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.0
i thought i compare the P? P2 in the first to 2P in the second?
 one year ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.1
for every 1 Ca3P2 you produce 2 PH3
 one year ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.1
Show me the moles of Ca3P2 and H2O
 one year ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ 6.18 }{ 182.18 }=.033922\] \[\frac{ 9.49 }{ 18 }=.52722\] \[\frac{ .52722 }{ .033922 }=15.542\] 15>6 so Ca3P2 is the limiting reactant right?
 one year ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.1
The way I do it is usually convert moles of reagent to product then see which gives me the least product (0.52722/6)2 = (0.033922/1)2 =
 one year ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.1
doing it this way also gives you the moles of product you have so its not like it is a huge hassle
 one year ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.0
what's the *2 for?
 one year ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.1
you produce 2 PH3
 one year ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.0
ok so i should have (.03392)*2 moles of PH3
 one year ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.1
yes
 one year ago

Jusaquikie Group TitleBest ResponseYou've already chosen the best response.0
then i multiply that by the MM of PH3 and i get the right answer. Thank you very much for your time it's clearer now.
 one year ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.1
yup
 one year ago
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