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Can u please help me with #38 I HAVE TRIED SO HARD ON IT and still cant get the answer please help:)? http://cbuddman.files.wordpress.com/2009/08/final-review-part-2.pdf
first you would need to find the area of the rectangle. Then you would find the area of the triangle with the formula A = 1/2 B H. To find the height you would need to sin rule.
have you learnt of special triangles?
30 60 90...45 45 90..i learned them
if you used the sin rule the length opposite 60 is \[\sqrt{48}\]
they want the area of this question right?
if you used the sin rule again you would find the bottom length to be equal to 4.
so the area of the triangle is equal to 8 root 3. \[8\sqrt{3}\]
ok.. the area of the traingle is 1/2 b h right? 1/2 * 4 * \[\sqrt{48}\] I have gotten this by using right angle trig? sin cos tan?
1/2 * 4 * \[\sqrt{48}\] = \[\sqrt{192}\] which is simplified to be\[8\sqrt{3}\]
so now i know that whats next?
well i got the area of the triangle so all you need now is area of rectangle and add them together
and sorry this has nothing to do with special triangles
ill complete it for you... (hope you can understand this) the bottom of the rectangle is equal to 6 ( 10-4) the length is \[\sqrt{48}\] so its \[\sqrt{48}\] * 6 which is \[24\sqrt{3}\] so now we add these area together which is \[32\sqrt{3}\]
do you understand it if you dont ill explain it again :)
i thought the bottom rectangle was 4?
It says on the diagram the whole length which is the triangle and rectangle is equal to 10. The bottom of the triangle is 4. So the rectangle is 10-4. which is 6
if you dont mind giving me a medal :) please do
click best response lol
OH lol ok i will wait hold up wat do i add to get 32√3 lol
well the area of the triangle and area of rectangle which is 24 root 3 + 8 root 3