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Can u please help me with #38 I HAVE TRIED SO HARD ON IT and still cant get the answer please help:)?
http://cbuddman.files.wordpress.com/2009/08/finalreviewpart2.pdf
 one year ago
 one year ago
Can u please help me with #38 I HAVE TRIED SO HARD ON IT and still cant get the answer please help:)? http://cbuddman.files.wordpress.com/2009/08/finalreviewpart2.pdf
 one year ago
 one year ago

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KuoministersBest ResponseYou've already chosen the best response.2
first you would need to find the area of the rectangle. Then you would find the area of the triangle with the formula A = 1/2 B H. To find the height you would need to sin rule.
 one year ago

KuoministersBest ResponseYou've already chosen the best response.2
have you learnt of special triangles?
 one year ago

laBest ResponseYou've already chosen the best response.0
30 60 90...45 45 90..i learned them
 one year ago

KuoministersBest ResponseYou've already chosen the best response.2
if you used the sin rule the length opposite 60 is \[\sqrt{48}\]
 one year ago

KuoministersBest ResponseYou've already chosen the best response.2
they want the area of this question right?
 one year ago

KuoministersBest ResponseYou've already chosen the best response.2
if you used the sin rule again you would find the bottom length to be equal to 4.
 one year ago

KuoministersBest ResponseYou've already chosen the best response.2
so the area of the triangle is equal to 8 root 3. \[8\sqrt{3}\]
 one year ago

KuoministersBest ResponseYou've already chosen the best response.2
ok.. the area of the traingle is 1/2 b h right? 1/2 * 4 * \[\sqrt{48}\] I have gotten this by using right angle trig? sin cos tan?
 one year ago

KuoministersBest ResponseYou've already chosen the best response.2
1/2 * 4 * \[\sqrt{48}\] = \[\sqrt{192}\] which is simplified to be\[8\sqrt{3}\]
 one year ago

laBest ResponseYou've already chosen the best response.0
so now i know that whats next?
 one year ago

KuoministersBest ResponseYou've already chosen the best response.2
well i got the area of the triangle so all you need now is area of rectangle and add them together
 one year ago

KuoministersBest ResponseYou've already chosen the best response.2
and sorry this has nothing to do with special triangles
 one year ago

KuoministersBest ResponseYou've already chosen the best response.2
ill complete it for you... (hope you can understand this) the bottom of the rectangle is equal to 6 ( 104) the length is \[\sqrt{48}\] so its \[\sqrt{48}\] * 6 which is \[24\sqrt{3}\] so now we add these area together which is \[32\sqrt{3}\]
 one year ago

KuoministersBest ResponseYou've already chosen the best response.2
do you understand it if you dont ill explain it again :)
 one year ago

laBest ResponseYou've already chosen the best response.0
i thought the bottom rectangle was 4?
 one year ago

KuoministersBest ResponseYou've already chosen the best response.2
It says on the diagram the whole length which is the triangle and rectangle is equal to 10. The bottom of the triangle is 4. So the rectangle is 104. which is 6
 one year ago

laBest ResponseYou've already chosen the best response.0
oh okay! THANK U SO MUCH!:)
 one year ago

KuoministersBest ResponseYou've already chosen the best response.2
if you dont mind giving me a medal :) please do
 one year ago

KuoministersBest ResponseYou've already chosen the best response.2
click best response lol
 one year ago

laBest ResponseYou've already chosen the best response.0
OH lol ok i will wait hold up wat do i add to get 32√3 lol
 one year ago

KuoministersBest ResponseYou've already chosen the best response.2
well the area of the triangle and area of rectangle which is 24 root 3 + 8 root 3
 one year ago
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