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anonymous
 3 years ago
Last question i promise...... DF bisects EDG. Find FG. The diagram is not to scale.
anonymous
 3 years ago
Last question i promise...... DF bisects EDG. Find FG. The diagram is not to scale.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0There is a theorem that states that in a situation exactly like this, (right angles on the bisector, etc.) the two lengths, FE and FG are congruent. So, set them equal to each other. n + 9 = 4n  6 Solve for n and plug it back in to either n + 9 or 4n  6 to get the answer.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I am honestly still very confused....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What are you confused ON?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ok. Do you know how to solve for n in the equation: n + 9 = 4n  6?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thats the part i keep getting stuck on.... i always end up with n=3 somehow

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ok I'll get you closer. n + 9 = 4n  6 This is the equation that you set up using geometry. n  n + 9 = 4n  n  6 Subtract n from both sides. 0 + 9 = 3n  6 Simplify by combining like terms. (n  n = 0) 9 = 3n  6 0 + anything is still that number. 9 + 6 = 3n  6 + 6 Add 6 to both sides to get the constant (number without an x) together. 15 = 3n Simplify by combining like terms. 15 ÷ 3 = 3n ÷ 3 Divide both sides by 3 in order to further isolate n. 5 = n or n = 5 (Interchangeable) Do you see how I got n? Now, use this "n" and plug it into 4n  6 because FG = 4n  6 FG = 4n  6 FG = 4(5)  6 Can you finish up?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yup :) FG = 14 Do you kinda sort of see how I got n?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes and thank you so much for going easy on me. Im not very good at geometry ><

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Don't worry about it! Everybody can have trouble at math and it's understandable. :)
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