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emcrazy14

  • 3 years ago

Please help with the last part of the attached question. O_o

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  1. emcrazy14
    • 3 years ago
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  2. Mashy
    • 3 years ago
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    ok so at at the required moment of time!.. you see only 4 buckets contribute to the momentum .. !!

  3. emcrazy14
    • 3 years ago
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    @Mashy: Umm. I think only buckets 2,3 and 4 would produce a moment about the centre of the wheel. But I don't know how to calculate it.

  4. Shadowys
    • 3 years ago
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    yes. 2,3,4 but not one. taking moment around the axis, \(\Sigma M= (W_2+W_3+W_4) \times 1.6m \)

  5. Shadowys
    • 3 years ago
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    bucket 1 has force line distance to axis=0, the others have no force line.

  6. Mashy
    • 3 years ago
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    shadow thats wrong.. you cannot take 1.6m ..moment is calculate as the force multiplied by the perpendicular distance from the centre!!

  7. Shadowys
    • 3 years ago
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    lol actually, yes, but to simplify calculations my teacher taught us a trick: to extend the force vectors and take the distance from the center. Yes, that's a lil' illegal, but it can simplify question sols like this one :P

  8. Mashy
    • 3 years ago
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    no.. i ll upload pic wiat!

  9. Mashy
    • 3 years ago
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  10. Mashy
    • 3 years ago
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    and what you are saying is the CORRECT way of taking the perpendicular distance.. its not illegal.. its perfect!

  11. Shadowys
    • 3 years ago
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    lol it is quite magical.

  12. emcrazy14
    • 3 years ago
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    @Mashy: Ok, so for x and z, I find the perpendicular distance by the formula sin45x1.6, right? And then multiply both of them by 400? For y, I simply multiply 1.6 by 400 to get the moment about the centre? Finally, I add the three values to get the resultant moment. Am I right so far?

  13. Shadowys
    • 3 years ago
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    yup! :)

  14. emcrazy14
    • 3 years ago
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    Thank you so much @Shadowys ! :D

  15. Shadowys
    • 3 years ago
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    you're welcome :)

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