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emcrazy14
Group Title
Please help with the last part of the attached question. O_o
 2 years ago
 2 years ago
emcrazy14 Group Title
Please help with the last part of the attached question. O_o
 2 years ago
 2 years ago

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Mashy Group TitleBest ResponseYou've already chosen the best response.1
ok so at at the required moment of time!.. you see only 4 buckets contribute to the momentum .. !!
 2 years ago

emcrazy14 Group TitleBest ResponseYou've already chosen the best response.0
@Mashy: Umm. I think only buckets 2,3 and 4 would produce a moment about the centre of the wheel. But I don't know how to calculate it.
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.0
yes. 2,3,4 but not one. taking moment around the axis, \(\Sigma M= (W_2+W_3+W_4) \times 1.6m \)
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.0
bucket 1 has force line distance to axis=0, the others have no force line.
 2 years ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
shadow thats wrong.. you cannot take 1.6m ..moment is calculate as the force multiplied by the perpendicular distance from the centre!!
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.0
lol actually, yes, but to simplify calculations my teacher taught us a trick: to extend the force vectors and take the distance from the center. Yes, that's a lil' illegal, but it can simplify question sols like this one :P
 2 years ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
no.. i ll upload pic wiat!
 2 years ago

Mashy Group TitleBest ResponseYou've already chosen the best response.1
and what you are saying is the CORRECT way of taking the perpendicular distance.. its not illegal.. its perfect!
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.0
lol it is quite magical.
 2 years ago

emcrazy14 Group TitleBest ResponseYou've already chosen the best response.0
@Mashy: Ok, so for x and z, I find the perpendicular distance by the formula sin45x1.6, right? And then multiply both of them by 400? For y, I simply multiply 1.6 by 400 to get the moment about the centre? Finally, I add the three values to get the resultant moment. Am I right so far?
 2 years ago

emcrazy14 Group TitleBest ResponseYou've already chosen the best response.0
Thank you so much @Shadowys ! :D
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.0
you're welcome :)
 2 years ago
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