anonymous
  • anonymous
Please help with the last part of the attached question. O_o
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
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anonymous
  • anonymous
ok so at at the required moment of time!.. you see only 4 buckets contribute to the momentum .. !!
anonymous
  • anonymous
@Mashy: Umm. I think only buckets 2,3 and 4 would produce a moment about the centre of the wheel. But I don't know how to calculate it.

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anonymous
  • anonymous
yes. 2,3,4 but not one. taking moment around the axis, \(\Sigma M= (W_2+W_3+W_4) \times 1.6m \)
anonymous
  • anonymous
bucket 1 has force line distance to axis=0, the others have no force line.
anonymous
  • anonymous
shadow thats wrong.. you cannot take 1.6m ..moment is calculate as the force multiplied by the perpendicular distance from the centre!!
anonymous
  • anonymous
lol actually, yes, but to simplify calculations my teacher taught us a trick: to extend the force vectors and take the distance from the center. Yes, that's a lil' illegal, but it can simplify question sols like this one :P
anonymous
  • anonymous
no.. i ll upload pic wiat!
anonymous
  • anonymous
anonymous
  • anonymous
and what you are saying is the CORRECT way of taking the perpendicular distance.. its not illegal.. its perfect!
anonymous
  • anonymous
lol it is quite magical.
anonymous
  • anonymous
@Mashy: Ok, so for x and z, I find the perpendicular distance by the formula sin45x1.6, right? And then multiply both of them by 400? For y, I simply multiply 1.6 by 400 to get the moment about the centre? Finally, I add the three values to get the resultant moment. Am I right so far?
anonymous
  • anonymous
yup! :)
anonymous
  • anonymous
Thank you so much @Shadowys ! :D
anonymous
  • anonymous
you're welcome :)

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