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if it has a half life of 650 time units it means every 650 time units 1/2 of the samle dissapears.

Yep. :) How would I find the rate of decay, though?

halflife= -ln2/k
that is the half life equation

I have a formula \[N=N _{0}e ^{kt}\]
How/where would I plug everything in?

I know spectrum

i gave him all right answers

for his teset
he did good to

I think they are asking for k
you got N=1/2No
t=650
so you plug all numbers in and find k

\[N=\frac{ 1 }{ 2 }N _{0}^{650k}\]
Okay, so what do I do next?

Would I put some test number in for No? Like 100 or something?

no,|dw:1354966748637:dw| you plug 1/2No for Nthen you can simplify for No

|dw:1354967053153:dw|

|dw:1354952485674:dw|

|dw:1354952600983:dw|

|dw:1354952743876:dw|

|dw:1354953110349:dw|

I think now it makes sense. Doesn't it?

KIS means keep it simple.

Derp still need help understanding =/

@Outkast3r09 : same thing I did. That is why I was confused with @mahmit2012 had done

\[\frac{dP}{dt}=kP\]
\[\frac{dP}{dt}-kP=0\]
\[e^{\int{kdt}}=e^{kt+c}=ce^{kt}\]

you integrate the left side you'll just get that and the right side will be P