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anonymous
 3 years ago
if F(t) and G(t) are of exponential order and L{F(t)}=L{G(t)} prove that F(t)=G(t). Can anyone help me prove this question plz =)
anonymous
 3 years ago
if F(t) and G(t) are of exponential order and L{F(t)}=L{G(t)} prove that F(t)=G(t). Can anyone help me prove this question plz =)

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UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.0is L for \(\mathcal L\)aplace transform ?

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.0when you say \[\mathcal L\{F(t)\}=\mathcal L\{G(t)\}\] do you mean \[\mathcal L\{f(t)\}=\mathcal L\{g(t)\}\]\[\qquad F(s)=G(s)\]?

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.0or do you mean the laplace transforms of, the laplace transforms of the functions are equal /

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0laplace of this function are equal and i want to prove that the function also equal...but dunno to start it....can u help me plz

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i am the same person that ask for this question.............actually this is a laplace transform theorem of derivatives............i need to prove this theorem.......the laplace for F(t)=G(t)
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