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farahkibri

  • 2 years ago

if F(t) and G(t) are of exponential order and L{F(t)}=L{G(t)} prove that F(t)=G(t). Can anyone help me prove this question plz =)

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  1. UnkleRhaukus
    • 2 years ago
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    is L for \(\mathcal L\)aplace transform ?

  2. farahkibri
    • 2 years ago
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    yes

  3. UnkleRhaukus
    • 2 years ago
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    when you say \[\mathcal L\{F(t)\}=\mathcal L\{G(t)\}\] do you mean \[\mathcal L\{f(t)\}=\mathcal L\{g(t)\}\]\[\qquad F(s)=G(s)\]?

  4. UnkleRhaukus
    • 2 years ago
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    or do you mean the laplace transforms of, the laplace transforms of the functions are equal /

  5. farahkibri
    • 2 years ago
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    laplace of this function are equal and i want to prove that the function also equal...but dunno to start it....can u help me plz

  6. farahin_kibri
    • 2 years ago
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    i am the same person that ask for this question.............actually this is a laplace transform theorem of derivatives............i need to prove this theorem.......the laplace for F(t)=G(t)

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