Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • 3 years ago

An isolated conducting sphere with radius \(R=6.85\text{cm}\) has charge \(Q=1.25nC\) a) how much potential energy is stored in the electric field of this charged conductor? b)what is the energy density at the surface of the sphere? c)what is the radius \(R_0\) of an imaginary spherical surface such that half of the stored potential energy lies within it?

  • This Question is Closed
  1. richyw
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    my attempts: a)\[U=\frac{Q^2}{2C}=\frac{Q^2}{8\pi\epsilon_0R}\]b)\[u=\frac{1}{2}\epsilon_0E^2\]\[u=\frac{1}{2}\epsilon_0\left(\frac{1}{4\pi\epsilon_0}\frac{Q}{R^2}\right)^2\]\[u=\frac{Q^2}{32\pi^2\epsilon_0R^4}\] c) unsure!

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy