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BelleFlower Group TitleBest ResponseYou've already chosen the best response.0
Help with Q12! :)
 one year ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.1
\[P=(2+\sqrt{5})^{2n1}\] \[P=\frac{ (2+\sqrt{5})^{2n}(2\sqrt{5}) }{ (2+\sqrt{5})(2\sqrt{5}) }\] \[P=\frac{ [(2+\sqrt{5})^{2}]^{n}(2\sqrt{5}) }{ 45 }\]
 one year ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.1
can you try now the next step?
 one year ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.1
@BelleFlower
 one year ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.1
\[P=\frac{ (9+4\sqrt{5})^{n}(2+\sqrt{5}) }{ 1 }\] P=\[P=(\sqrt{5}2)(9+4\sqrt{5})^{n}\]
 one year ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.1
you can continue the next step
 one year ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.1
thats ok :D
 one year ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.1
check on this one \[\sqrt{(4)^{2}}\sqrt{5}=\sqrt{16*5}=\sqrt{80}\]
 one year ago

BelleFlower Group TitleBest ResponseYou've already chosen the best response.0
OH OH okay thank you so much! I got it now!!
 one year ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.1
YW good luck now ... :D
 one year ago
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