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BelleFlower
 3 years ago
Please refer to image! Indices question
BelleFlower
 3 years ago
Please refer to image! Indices question

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mark_o.
 3 years ago
Best ResponseYou've already chosen the best response.1\[P=(2+\sqrt{5})^{2n1}\] \[P=\frac{ (2+\sqrt{5})^{2n}(2\sqrt{5}) }{ (2+\sqrt{5})(2\sqrt{5}) }\] \[P=\frac{ [(2+\sqrt{5})^{2}]^{n}(2\sqrt{5}) }{ 45 }\]

mark_o.
 3 years ago
Best ResponseYou've already chosen the best response.1can you try now the next step?

mark_o.
 3 years ago
Best ResponseYou've already chosen the best response.1\[P=\frac{ (9+4\sqrt{5})^{n}(2+\sqrt{5}) }{ 1 }\] P=\[P=(\sqrt{5}2)(9+4\sqrt{5})^{n}\]

mark_o.
 3 years ago
Best ResponseYou've already chosen the best response.1you can continue the next step

mark_o.
 3 years ago
Best ResponseYou've already chosen the best response.1check on this one \[\sqrt{(4)^{2}}\sqrt{5}=\sqrt{16*5}=\sqrt{80}\]

BelleFlower
 3 years ago
Best ResponseYou've already chosen the best response.0OH OH okay thank you so much! I got it now!!

mark_o.
 3 years ago
Best ResponseYou've already chosen the best response.1YW good luck now ... :D
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