A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Please refer to image! Indices question
anonymous
 3 years ago
Please refer to image! Indices question

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[P=(2+\sqrt{5})^{2n1}\] \[P=\frac{ (2+\sqrt{5})^{2n}(2\sqrt{5}) }{ (2+\sqrt{5})(2\sqrt{5}) }\] \[P=\frac{ [(2+\sqrt{5})^{2}]^{n}(2\sqrt{5}) }{ 45 }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can you try now the next step?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[P=\frac{ (9+4\sqrt{5})^{n}(2+\sqrt{5}) }{ 1 }\] P=\[P=(\sqrt{5}2)(9+4\sqrt{5})^{n}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you can continue the next step

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0check on this one \[\sqrt{(4)^{2}}\sqrt{5}=\sqrt{16*5}=\sqrt{80}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0OH OH okay thank you so much! I got it now!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0YW good luck now ... :D
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.