BelleFlower
Please refer to image! Indices question



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hba
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k

BelleFlower
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Help with Q12! :)

mark_o.
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\[P=(2+\sqrt{5})^{2n1}\]
\[P=\frac{ (2+\sqrt{5})^{2n}(2\sqrt{5}) }{ (2+\sqrt{5})(2\sqrt{5}) }\]
\[P=\frac{ [(2+\sqrt{5})^{2}]^{n}(2\sqrt{5}) }{ 45 }\]

mark_o.
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can you try now the next step?

mark_o.
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@BelleFlower

mark_o.
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\[P=\frac{ (9+4\sqrt{5})^{n}(2+\sqrt{5}) }{ 1 }\]
P=\[P=(\sqrt{5}2)(9+4\sqrt{5})^{n}\]

mark_o.
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you can continue the next step

mark_o.
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thats ok :D

mark_o.
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check on this one
\[\sqrt{(4)^{2}}\sqrt{5}=\sqrt{16*5}=\sqrt{80}\]

BelleFlower
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OH OH okay thank you so much! I got it now!!

mark_o.
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YW good luck now ... :D