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nestor18
Group Title
What does the series converge to?
3/59/25+27/125.......
This is a geometric alternating series where A=3/5 and r=3^n/5^n? I think how would I get to its convergence?
 one year ago
 one year ago
nestor18 Group Title
What does the series converge to? 3/59/25+27/125....... This is a geometric alternating series where A=3/5 and r=3^n/5^n? I think how would I get to its convergence?
 one year ago
 one year ago

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gasgengar Group TitleBest ResponseYou've already chosen the best response.0
The summation of these geometric series to infinity is = a[(1R^(n+1))/(1R)] I assume you know how this answer comes from, so a = 3/5, R = (1) (3/5) and n tends to infinity you'll get the answer = (3/5)/(1+3/5) = 3/8
 one year ago

nestor18 Group TitleBest ResponseYou've already chosen the best response.0
I had a brain fart, series was not my strong suit in Calc 2, we barely touched on it.Thanks
 one year ago

cinar Group TitleBest ResponseYou've already chosen the best response.0
\[\Large\sum_{n=1}^{\infty}{(1)^{n+1}}(\frac{3}{5})^n\]
 one year ago

nestor18 Group TitleBest ResponseYou've already chosen the best response.0
I originally put the standard A/1r and got 15/10, but then I noticed it was an alternating series
 one year ago

cinar Group TitleBest ResponseYou've already chosen the best response.0
answer is 3/8
 one year ago
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