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Kainui

  • 3 years ago

e^x=-x solve for x

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  1. shahzadjalbani
    • 3 years ago
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    apply ln (natural log) of both sides

  2. waleed_imtiaz
    • 3 years ago
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    what I have to do here? take left hand side... =e^x ...take log ... xlne =x....=R.H.S

  3. Kainui
    • 3 years ago
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    \[x=\ln(-x)\]

  4. Kainui
    • 3 years ago
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    All this tells me is that x must be negative, otherwise the log function will be broken.

  5. Kainui
    • 3 years ago
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    I know there's an answer because the graphs of y=e^x and y=-x intersect at some point.

  6. waleed_imtiaz
    • 3 years ago
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    x should be positive I think so thats why we take mood like ln|x|

  7. anonymous
    • 3 years ago
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    good luck algebra will not do it

  8. anonymous
    • 3 years ago
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    you will use technology or numerical methods

  9. anonymous
    • 3 years ago
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    http://www.wolframalpha.com/input/?i=e^x%3D-x

  10. Kainui
    • 3 years ago
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    Damn, there's no alternative trick then? Hmm.

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