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shahzadjalbani Group TitleBest ResponseYou've already chosen the best response.0
apply ln (natural log) of both sides
 one year ago

waleed_imtiaz Group TitleBest ResponseYou've already chosen the best response.0
what I have to do here? take left hand side... =e^x ...take log ... xlne =x....=R.H.S
 one year ago

Kainui Group TitleBest ResponseYou've already chosen the best response.0
\[x=\ln(x)\]
 one year ago

Kainui Group TitleBest ResponseYou've already chosen the best response.0
All this tells me is that x must be negative, otherwise the log function will be broken.
 one year ago

Kainui Group TitleBest ResponseYou've already chosen the best response.0
I know there's an answer because the graphs of y=e^x and y=x intersect at some point.
 one year ago

waleed_imtiaz Group TitleBest ResponseYou've already chosen the best response.0
x should be positive I think so thats why we take mood like lnx
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
good luck algebra will not do it
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
you will use technology or numerical methods
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
http://www.wolframalpha.com/input/?i=e^x%3Dx
 one year ago

Kainui Group TitleBest ResponseYou've already chosen the best response.0
Damn, there's no alternative trick then? Hmm.
 one year ago
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