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e^x=-x solve for x

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apply ln (natural log) of both sides
what I have to do here? take left hand side... =e^x ...take log ... xlne =x....=R.H.S

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All this tells me is that x must be negative, otherwise the log function will be broken.
I know there's an answer because the graphs of y=e^x and y=-x intersect at some point.
x should be positive I think so thats why we take mood like ln|x|
good luck algebra will not do it
you will use technology or numerical methods^x%3D-x
Damn, there's no alternative trick then? Hmm.

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