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Kainui Group Title

e^x=-x solve for x

  • one year ago
  • one year ago

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  1. shahzadjalbani Group Title
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    apply ln (natural log) of both sides

    • one year ago
  2. waleed_imtiaz Group Title
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    what I have to do here? take left hand side... =e^x ...take log ... xlne =x....=R.H.S

    • one year ago
  3. Kainui Group Title
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    \[x=\ln(-x)\]

    • one year ago
  4. Kainui Group Title
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    All this tells me is that x must be negative, otherwise the log function will be broken.

    • one year ago
  5. Kainui Group Title
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    I know there's an answer because the graphs of y=e^x and y=-x intersect at some point.

    • one year ago
  6. waleed_imtiaz Group Title
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    x should be positive I think so thats why we take mood like ln|x|

    • one year ago
  7. satellite73 Group Title
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    good luck algebra will not do it

    • one year ago
  8. satellite73 Group Title
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    you will use technology or numerical methods

    • one year ago
  9. satellite73 Group Title
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    http://www.wolframalpha.com/input/?i=e^x%3D-x

    • one year ago
  10. Kainui Group Title
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    Damn, there's no alternative trick then? Hmm.

    • one year ago
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