anonymous
  • anonymous
I REALLY NEED HELP FAST! I WILL BECOME YOUR FAN/GIVE YOU A MEDAL IF U HELP ME?!?!! Select the equations that are parallel and perpendicular to y = x + 5 and that pass through the point (-2, -1
Mathematics
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anonymous
  • anonymous
I REALLY NEED HELP FAST! I WILL BECOME YOUR FAN/GIVE YOU A MEDAL IF U HELP ME?!?!! Select the equations that are parallel and perpendicular to y = x + 5 and that pass through the point (-2, -1
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
parallel: y = -x - 1 perpendicular: y = x + 2 parallel: y = x - 1 perpendicular: y = -x + 1 parallel: y = x + 1 perpendicular: y = -x - 3 parallel: y = 2x - 2 perpendicular: y = -2x - 1
anonymous
  • anonymous
anonymous
  • anonymous
I don't know how to do this

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anonymous
  • anonymous
radar
  • radar
You can do this provided you understand the relationship between slopes of parallel vs perpendicular lines. Parallel lines will have the same slope (slopes are equal) Do you want to do the parallel line first?
anonymous
  • anonymous
Yes please!
anonymous
  • anonymous
Please hurry! I don't have much time cuz I have to go somewhere soon
radar
  • radar
O.K. we want to calculate a parallel line to y=x+5 and it goes through the point (-2,-1) (x=-2, y=-1) The slope is the coefficient of the x in the y=x+5 equation so it is 1 (positive 1). Slope is not more than the change in y divided by the change in x. Or slope = (y1-y2)/(x1-x2) For this equation 1 = (y-(-1))/(x-(-2) or|dw:1354996414474:dw| Did you follow ???
radar
  • radar
|dw:1354996541407:dw|
anonymous
  • anonymous
Okay!
anonymous
  • anonymous
The perpendicular is where I get messed up
radar
  • radar
Apparently you ran off. Well the perpendicula line will have a negative reciprocal of the slope of or line. That will be a -1.|dw:1354996665195:dw|
radar
  • radar
You should be able to select the correct response.
anonymous
  • anonymous
Ohh! Thank you so much!!
radar
  • radar
|dw:1354996778445:dw|
radar
  • radar
You are welcome, good luck with these.

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