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anonymous
 4 years ago
I REALLY NEED HELP FAST! I WILL BECOME YOUR FAN/GIVE YOU A MEDAL IF U HELP ME?!?!!
Select the equations that are parallel and perpendicular to y = x + 5 and that pass through the point (2, 1
anonymous
 4 years ago
I REALLY NEED HELP FAST! I WILL BECOME YOUR FAN/GIVE YOU A MEDAL IF U HELP ME?!?!! Select the equations that are parallel and perpendicular to y = x + 5 and that pass through the point (2, 1

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0parallel: y = x  1 perpendicular: y = x + 2 parallel: y = x  1 perpendicular: y = x + 1 parallel: y = x + 1 perpendicular: y = x  3 parallel: y = 2x  2 perpendicular: y = 2x  1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I don't know how to do this

radar
 4 years ago
Best ResponseYou've already chosen the best response.1You can do this provided you understand the relationship between slopes of parallel vs perpendicular lines. Parallel lines will have the same slope (slopes are equal) Do you want to do the parallel line first?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Please hurry! I don't have much time cuz I have to go somewhere soon

radar
 4 years ago
Best ResponseYou've already chosen the best response.1O.K. we want to calculate a parallel line to y=x+5 and it goes through the point (2,1) (x=2, y=1) The slope is the coefficient of the x in the y=x+5 equation so it is 1 (positive 1). Slope is not more than the change in y divided by the change in x. Or slope = (y1y2)/(x1x2) For this equation 1 = (y(1))/(x(2) ordw:1354996414474:dw Did you follow ???

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The perpendicular is where I get messed up

radar
 4 years ago
Best ResponseYou've already chosen the best response.1Apparently you ran off. Well the perpendicula line will have a negative reciprocal of the slope of or line. That will be a 1.dw:1354996665195:dw

radar
 4 years ago
Best ResponseYou've already chosen the best response.1You should be able to select the correct response.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ohh! Thank you so much!!

radar
 4 years ago
Best ResponseYou've already chosen the best response.1You are welcome, good luck with these.
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