## Nanoman 2 years ago Stochiochemistry question. Check my work

1. Nanoman

Ao2 is the equation, a23 is the question.

2. Nanoman

@dkenner @ganeshie8

3. Nanoman

@dpaInc

4. Nanoman

@AccessDenied

5. BluFoot

Alright for Ao2, there are 16 moles of CO2 forming for every 2 moles of C8H18 reacting. So there's 8 times more CO2 than C8H18. So the answer is 3.5*8. For a23, you have the same problem. There is 9 times more H2O forming than C8H18 reacting (18/2). So there should be a 9 in front of the H2O. The rest is fine.

6. Nanoman

Thanks. The picture for Ao2 is out of date, I fixed that problem. The equation says that there's 2C8H18 and 18H2O. Shouldn't that be the proper ratio?

7. BluFoot

Yes, that's the better way of doing it, you're right. It would give the same answer though of course.

8. Nanoman

So, 70.9704628 mL is the correct result?

9. BluFoot

No! You're writing it like 18 moles of H2O are forming for every mole of C8H18. It should be 9

10. BluFoot

Sorry I thought you were talking about something else in my last comment.

11. Nanoman

It's 18 mol of H2O for every 2 mol C8H18, so it's equivalent to 9/1 right?

12. Nanoman

@BluFoot

13. BluFoot

Yes, sorry I missed your reply somehow!

14. BluFoot

18/2=9/1