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Nanoman

  • 3 years ago

Stochiochemistry question. Check my work

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  1. Nanoman
    • 3 years ago
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    Ao2 is the equation, a23 is the question.

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  2. Nanoman
    • 3 years ago
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    @dkenner @ganeshie8

  3. Nanoman
    • 3 years ago
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    @dpaInc

  4. Nanoman
    • 3 years ago
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    @AccessDenied

  5. BluFoot
    • 3 years ago
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    Alright for Ao2, there are 16 moles of CO2 forming for every 2 moles of C8H18 reacting. So there's 8 times more CO2 than C8H18. So the answer is 3.5*8. For a23, you have the same problem. There is 9 times more H2O forming than C8H18 reacting (18/2). So there should be a 9 in front of the H2O. The rest is fine.

  6. Nanoman
    • 3 years ago
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    Thanks. The picture for Ao2 is out of date, I fixed that problem. The equation says that there's 2C8H18 and 18H2O. Shouldn't that be the proper ratio?

  7. BluFoot
    • 3 years ago
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    Yes, that's the better way of doing it, you're right. It would give the same answer though of course.

  8. Nanoman
    • 3 years ago
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    So, 70.9704628 mL is the correct result?

  9. BluFoot
    • 3 years ago
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    No! You're writing it like 18 moles of H2O are forming for every mole of C8H18. It should be 9

  10. BluFoot
    • 3 years ago
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    Sorry I thought you were talking about something else in my last comment.

  11. Nanoman
    • 3 years ago
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    It's 18 mol of H2O for every 2 mol C8H18, so it's equivalent to 9/1 right?

  12. Nanoman
    • 3 years ago
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    @BluFoot

  13. BluFoot
    • 3 years ago
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    Yes, sorry I missed your reply somehow!

  14. BluFoot
    • 3 years ago
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    18/2=9/1

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