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anonymous
 3 years ago
Stochiochemistry question. Check my work
anonymous
 3 years ago
Stochiochemistry question. Check my work

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ao2 is the equation, a23 is the question.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Alright for Ao2, there are 16 moles of CO2 forming for every 2 moles of C8H18 reacting. So there's 8 times more CO2 than C8H18. So the answer is 3.5*8. For a23, you have the same problem. There is 9 times more H2O forming than C8H18 reacting (18/2). So there should be a 9 in front of the H2O. The rest is fine.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks. The picture for Ao2 is out of date, I fixed that problem. The equation says that there's 2C8H18 and 18H2O. Shouldn't that be the proper ratio?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, that's the better way of doing it, you're right. It would give the same answer though of course.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So, 70.9704628 mL is the correct result?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No! You're writing it like 18 moles of H2O are forming for every mole of C8H18. It should be 9

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Sorry I thought you were talking about something else in my last comment.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It's 18 mol of H2O for every 2 mol C8H18, so it's equivalent to 9/1 right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, sorry I missed your reply somehow!
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