Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Please I really need help with this one.Find an equation of the circle passing through (6, 7) and tangent to the line y = 2x + 1 at (5, 11). Write your answer in standard form.

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
So to find the tangent line, you have to derive. You understand this part right?
And then to derive...y'=2
When you derive, you get the slope...So the slope of your tangent line is 2.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

So now you put this into point slope form y-7=2(x-6)
And then to put it into standard form you just do some algebra: y=2x-12+7-->2x-5
what would I get
y=2x-5
|dw:1355017036124:dw|
x^2+y^2=r^2 sub. x=6 y=7 find r=sqrt85
you should find coord. of center of circle..
you can use point-line distance formula to find coordinate of center..
http://mathworld.wolfram.com/Point-LineDistance2-Dimensional.html
So I just plug Xand Y into the equation ax+by+c=0 but how would I find a,b,c
y = 2x + 1 => 2x-y+1=0 a=2, b=-1, c=1
Right, and what would I do after that how, do I convert it in standard from for a circle
(x-x1)^2+(y-y1)^2=r^2 where x1 and x2 coordinate of center..
and x1 and y1 would be 6, and 7
no, you need to find it..

Not the answer you are looking for?

Search for more explanations.

Ask your own question