anonymous
  • anonymous
Please I really need help with this one.Find an equation of the circle passing through (6, 7) and tangent to the line y = 2x + 1 at (5, 11). Write your answer in standard form.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
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anonymous
  • anonymous
So to find the tangent line, you have to derive. You understand this part right?
anonymous
  • anonymous
And then to derive...y'=2
anonymous
  • anonymous
When you derive, you get the slope...So the slope of your tangent line is 2.

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anonymous
  • anonymous
So now you put this into point slope form y-7=2(x-6)
anonymous
  • anonymous
And then to put it into standard form you just do some algebra: y=2x-12+7-->2x-5
anonymous
  • anonymous
what would I get
anonymous
  • anonymous
y=2x-5
anonymous
  • anonymous
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anonymous
  • anonymous
x^2+y^2=r^2 sub. x=6 y=7 find r=sqrt85
anonymous
  • anonymous
you should find coord. of center of circle..
anonymous
  • anonymous
you can use point-line distance formula to find coordinate of center..
anonymous
  • anonymous
http://mathworld.wolfram.com/Point-LineDistance2-Dimensional.html
anonymous
  • anonymous
So I just plug Xand Y into the equation ax+by+c=0 but how would I find a,b,c
anonymous
  • anonymous
y = 2x + 1 => 2x-y+1=0 a=2, b=-1, c=1
anonymous
  • anonymous
Right, and what would I do after that how, do I convert it in standard from for a circle
anonymous
  • anonymous
(x-x1)^2+(y-y1)^2=r^2 where x1 and x2 coordinate of center..
anonymous
  • anonymous
and x1 and y1 would be 6, and 7
anonymous
  • anonymous
no, you need to find it..

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