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Sabrena

Solve this equation. (x-5)(4x+3)=0. Totally went blank. Any Help

  • one year ago
  • one year ago

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  1. Sabrena
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    |dw:1355012579897:dw| Can someone help me here...They have went over so many things that I am drawing a blank.

    • one year ago
  2. joshi
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    so since the product of both brackets is 0, we could say (x-5)=0 and (4x+3) =0

    • one year ago
  3. joshi
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    with me so far?

    • one year ago
  4. Sujay
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    \[(x-5)(4x-3)=0\] This is the original equation. So, either \[(x-5)=0\] or \[(4x-3)=0\]. So, \[x=5\] and \[4x=3\]. Simplify: \[x=5\] and \[x=\frac{ 4}{ 3 }\]. Final answer: \[\left\{ 5,\frac{ 4 }{ 3 } \right\}\].

    • one year ago
  5. Sujay
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    Sorry, I just noticed it is 4x+3, just do the same thing, but with a negative sign.

    • one year ago
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