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DogLuverSarah2012

  • 2 years ago

How can you find the standard form of an equation using 2 given points?

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  1. geoffb
    • 2 years ago
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    Calculate your slope and the y intercept.

  2. geoffb
    • 2 years ago
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    |dw:1355021981183:dw|

  3. geoffb
    • 2 years ago
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    If A is at \((x_{A}, y_{A})\) and B is at \((x_{B}, y_{B})\), then slope is \(\large \frac{y_{B} - y_{A}}{x_{B} - x_{A}}\)

  4. DogLuverSarah2012
    • 2 years ago
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    Ok so what do I do once I have the slope?

  5. geoffb
    • 2 years ago
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    Then you use it to find the y-intercept. Remember, the y-intercept is at point \((0, y_{C})\)

  6. geoffb
    • 2 years ago
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    So, if you used point A, you could use \(\large m = \frac{y_{C} - y_{A}}{0 - x_{A}}\)

  7. DogLuverSarah2012
    • 2 years ago
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    ok so once I have the y-intercept???

  8. geoffb
    • 2 years ago
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    Then put it in the form y = mx + b. m is the slope, and b is the y-intercept.

  9. DogLuverSarah2012
    • 2 years ago
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    Ok,I understand that part but how do i find teh standard form of the equation,my book says it would be Ax +By=C but it doesn texplain how to find the equation using 2 given points.

  10. geoffb
    • 2 years ago
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    Oh, sorry. I missed that part of your post. Standard form is just \(Ax + By = C\) (like you said). You can get it by rearranging your y = mx + b formula.

  11. geoffb
    • 2 years ago
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    Bring y and mx to the same side, to equal b.

  12. DogLuverSarah2012
    • 2 years ago
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    Ok so I have teh x and y intercepts figured out but how do I find C?

  13. geoffb
    • 2 years ago
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    C is just b (from y = mx + b)

  14. DogLuverSarah2012
    • 2 years ago
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    Ok thank you very much!!!

  15. geoffb
    • 2 years ago
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    You're welcome.

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