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anonymous
 3 years ago
cos^x(sec^2x1)
what pythagoream identiy to use?
anonymous
 3 years ago
cos^x(sec^2x1) what pythagoream identiy to use?

This Question is Closed

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1first multiply them out. like a(bc) = abac so whats cos^x(sec^2x1) = ...  ... ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeahhhhh right hartnn

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0cos^2x(sec^2x)  cos^2x1

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1yup, and you know what cos x * sec x = .. ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1\(\large \cos^2x(\sec^2x1)=\cos^2x\sec^2x\cos^2x = ...?\)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1can u simplify that ^ ? use the fact that cos x = 1/ sec x.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0should i use factorization in this

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1nopes. since, cos x = 1/ sec x what is cos x * sec x = ... ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0should i turn secant into cos

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1yes., do that...what u get ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1355024922967:dw

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1\(\large \cos^2x\sec^2x\cos^2x = 1 \cos^2 x=...?\)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1use th identity \(\huge \color{red}{\sin^2x+\cos^2x=1}\) yes, sin^2 x is correct :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thanks! this is hard cuz cuz i never know which identity to use :(

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1do u wanna know alternative way to solve this ? using other identity...

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1using \(\huge \color{red}{\sec^2x=1+\tan^2x}\) what can you write (sec^2x1)=...?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1and you can write tan^2 x as sin^2 x/ cos^2x

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1so, put (sec^2 x1) as sin^2 x/ cos^2x cos^2 x*( sin^2 x/ cos^2x) will again give you sin^2 x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1355025560186:dw
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