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hartnnBest ResponseYou've already chosen the best response.1
first multiply them out. like a(bc) = abac so whats cos^x(sec^2x1) = ...  ... ?
 one year ago

Lindsey11x16Best ResponseYou've already chosen the best response.0
cos^2x(sec^2x)  cos^2x1
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
yup, and you know what cos x * sec x = .. ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\(\large \cos^2x(\sec^2x1)=\cos^2x\sec^2x\cos^2x = ...?\)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
can u simplify that ^ ? use the fact that cos x = 1/ sec x.
 one year ago

Lindsey11x16Best ResponseYou've already chosen the best response.0
should i use factorization in this
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
nopes. since, cos x = 1/ sec x what is cos x * sec x = ... ?
 one year ago

Lindsey11x16Best ResponseYou've already chosen the best response.0
should i turn secant into cos
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
yes., do that...what u get ?
 one year ago

Lindsey11x16Best ResponseYou've already chosen the best response.0
dw:1355024922967:dw
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\(\large \cos^2x\sec^2x\cos^2x = 1 \cos^2 x=...?\)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
use th identity \(\huge \color{red}{\sin^2x+\cos^2x=1}\) yes, sin^2 x is correct :)
 one year ago

Lindsey11x16Best ResponseYou've already chosen the best response.0
thanks! this is hard cuz cuz i never know which identity to use :(
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
do u wanna know alternative way to solve this ? using other identity...
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
using \(\huge \color{red}{\sec^2x=1+\tan^2x}\) what can you write (sec^2x1)=...?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
and you can write tan^2 x as sin^2 x/ cos^2x
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
so, put (sec^2 x1) as sin^2 x/ cos^2x cos^2 x*( sin^2 x/ cos^2x) will again give you sin^2 x
 one year ago

Lindsey11x16Best ResponseYou've already chosen the best response.0
dw:1355025560186:dw
 one year ago
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