What is the inverse of the function f(x)=1/3x-2?

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What is the inverse of the function f(x)=1/3x-2?

Mathematics
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y=(1/3)x-2 Switch y&x and solve x=(1/3)y-2
So what is the next step you would do?
idk

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Other answers:

So we want to get y by itself. Lets add 2 to each side.
\[x+2 = \frac{ 1 }{ 3 }y\]
Does that make sense?
So how will we now "move" the 1/3?
Okay. f(x)=1/3x-2 Take f(x) = y y = 1/(3x - 2) y*(3x - 2) = 1 3xy - 2y = 1 -1 - 2y= - 3xy -(1 + 2y) = -3xy 1 + 2y = 3xy (1 + 2y)/y = 3x (1 + 2y)/3y = x Lastly, replace y with x, we have: (1 + 2x)/3x = y Which is the inverse.
Wait, is it \[F(x) = \frac{ 1 }{ 3x - 2 }?\]
Or is it \[F(x) = \frac{ 1 }{ 3 }x - 2?\]
Wouldn't it be 3(x+2)=y y=3x+6 \[f ^{-1}(x) = 3x+6\]
thats what i got but i got -3x but i see what i did wrong, thank you
Thank you.

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