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- anonymous

How would I solve this equation: 10(2x + 7) = 90

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- anonymous

How would I solve this equation: 10(2x + 7) = 90

- schrodinger

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- anonymous

|dw:1355034090176:dw|

- calculusfunctions

If you have an equation of the form
a(bx + c) = d
Then
i). divide both sides by a
ii). add the opposite of c to both sides
iii). divide both sides by b
OR
i). multiply a by (bx + c) by the distributive property to obtain (ab)x + ac = d
ii). add the opposite of ac to both sides
iii). divide both sides by ab
Note: @izziewoods and @winterfez we don't give out answers or do an entire solution except for the final step, because that does not help the person wanting help to learn. So either teach, otherwise you may be reported. I suggest you erase your answers.

- anonymous

\[10(2x+7)=90\]divide both sides by 10:\[2x+7=9\]subtract 7:\[2x=2\]divide both sides by 2 to isolate x:\[x-~...?\]

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- calculusfunctions

@yummydum please read the warning above, about giving out answers!

- anonymous

Thanks.

- anonymous

the main goal is to get x alone, of course, so when you see parenthesis, automatically look at if you can get rid of the stuff outside the parenthesis first. once you done that get the term containing x isolated at one side of the equal sign. if then the x is still not alone, divide to isolate.

- calculusfunctions

Welcome @ zordoloom I assume you understand?

- anonymous

Yep

- calculusfunctions

Great!

- anonymous

@calculusfunctions woops I'm sorry I just signed up and I didn't know the rules

- calculusfunctions

No worries @izziewoods as long as it doesn't happen again.

- anonymous

@calculusfunctions it won't happen again! thank you!=)

- anonymous

x=1

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