Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Alfonso92
Group Title
f(x)={x if pi/2<x<pi/2, pix if pi/2<x<3pi/2}, How do I demonstrate that it is an odd function?
 one year ago
 one year ago
Alfonso92 Group Title
f(x)={x if pi/2<x<pi/2, pix if pi/2<x<3pi/2}, How do I demonstrate that it is an odd function?
 one year ago
 one year ago

This Question is Open

ZeHanz Group TitleBest ResponseYou've already chosen the best response.1
I don't think it is odd. A function is odd if f(x) =f(x) for each x in the domain of f. This implies that the domain should be centered around 0 (or that is consists of all real numbers). Here, f(pi) = 0, while f(pi) is not even defined. So f cannot be odd.
 one year ago

ZeHanz Group TitleBest ResponseYou've already chosen the best response.1
On the other hand, this function is symmetric in x = pi/2, which means that f(pi/2 x) = f(pi/2 + x), for every x in the domain.
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.