anonymous
  • anonymous
If a radius bisects a chord, then the lengths of the parts of the radius on either side of the chord are equal. A. Given B. Unfounded C. Definition of supplementary angles D. Definition of a bisector E. Definition of radius I don't get this at all... can anybody explain this to me really easily?
Mathematics
katieb
  • katieb
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ganeshie8
  • ganeshie8
the question talks about radius and chords. so lets begin wid drawing a circle, its radius and some chord
anonymous
  • anonymous
ok!
anonymous
  • anonymous
oh do you want me to draw it?

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ganeshie8
  • ganeshie8
yes if u can it wud be good :)
anonymous
  • anonymous
|dw:1355040041898:dw|
anonymous
  • anonymous
so line segment CD is the chord and the radius is line segment AB
anonymous
  • anonymous
am I right so far?
anonymous
  • anonymous
what should I do next?
mathstudent55
  • mathstudent55
Didn't we just do this?
anonymous
  • anonymous
@mathstudent55 yes but I am not sure with my answer. you said that just because a chord is perpendicular to a radius, it does not necessarily bisect the radius right?
mathstudent55
  • mathstudent55
right
anonymous
  • anonymous
so this question is asking about the length of the radius? like I'm not understanding the question well
mathstudent55
  • mathstudent55
You knew from before that if a chord is perpendicular to a radius, the radius bisects the chord. Here they're asking you the other way around. If a chord is perpendicular to a radius, does the chord bisect the radius?
mathstudent55
  • mathstudent55
|dw:1355040622608:dw|
anonymous
  • anonymous
oh then the answer is no
mathstudent55
  • mathstudent55
Look at the three chords, one you drew and two I added. Let's say the radius is perpendicular to all 3 chords. Then you know the radius bisects all three chords. Now look at the chords. Only one chord can possibly be a bisector of the radius, but certainly not all three. In reality, there is an infinite number of chords that are perpendicular to that radius, and only one bisects the radius. So to conclude that with any chord that is perpendicular to a radius, that chord bisects the radius it's unfounded.
anonymous
  • anonymous
ohhhhh ok I think I get it!! ohohoh omg I get it!!! yeah!!!only one chord bisects the radius!!
mathstudent55
  • mathstudent55
Right, but the radius bisects every chord that it is perpendicular to.
anonymous
  • anonymous
yes yes!!! thank you thank you thank you!!! I totally get it now!! you explained it to me really easily!!
mathstudent55
  • mathstudent55
ok, great, you're welcome

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