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izziewoods
Group Title
If a radius bisects a chord, then the lengths of the parts of the radius on either side of the chord are equal.
A. Given
B. Unfounded
C. Definition of supplementary angles
D. Definition of a bisector
E. Definition of radius
I don't get this at all... can anybody explain this to me really easily?
 one year ago
 one year ago
izziewoods Group Title
If a radius bisects a chord, then the lengths of the parts of the radius on either side of the chord are equal. A. Given B. Unfounded C. Definition of supplementary angles D. Definition of a bisector E. Definition of radius I don't get this at all... can anybody explain this to me really easily?
 one year ago
 one year ago

This Question is Closed

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.0
the question talks about radius and chords. so lets begin wid drawing a circle, its radius and some chord
 one year ago

izziewoods Group TitleBest ResponseYou've already chosen the best response.0
oh do you want me to draw it?
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.0
yes if u can it wud be good :)
 one year ago

izziewoods Group TitleBest ResponseYou've already chosen the best response.0
dw:1355040041898:dw
 one year ago

izziewoods Group TitleBest ResponseYou've already chosen the best response.0
so line segment CD is the chord and the radius is line segment AB
 one year ago

izziewoods Group TitleBest ResponseYou've already chosen the best response.0
am I right so far?
 one year ago

izziewoods Group TitleBest ResponseYou've already chosen the best response.0
what should I do next?
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.2
Didn't we just do this?
 one year ago

izziewoods Group TitleBest ResponseYou've already chosen the best response.0
@mathstudent55 yes but I am not sure with my answer. you said that just because a chord is perpendicular to a radius, it does not necessarily bisect the radius right?
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.2
right
 one year ago

izziewoods Group TitleBest ResponseYou've already chosen the best response.0
so this question is asking about the length of the radius? like I'm not understanding the question well
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.2
You knew from before that if a chord is perpendicular to a radius, the radius bisects the chord. Here they're asking you the other way around. If a chord is perpendicular to a radius, does the chord bisect the radius?
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.2
dw:1355040622608:dw
 one year ago

izziewoods Group TitleBest ResponseYou've already chosen the best response.0
oh then the answer is no
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.2
Look at the three chords, one you drew and two I added. Let's say the radius is perpendicular to all 3 chords. Then you know the radius bisects all three chords. Now look at the chords. Only one chord can possibly be a bisector of the radius, but certainly not all three. In reality, there is an infinite number of chords that are perpendicular to that radius, and only one bisects the radius. So to conclude that with any chord that is perpendicular to a radius, that chord bisects the radius it's unfounded.
 one year ago

izziewoods Group TitleBest ResponseYou've already chosen the best response.0
ohhhhh ok I think I get it!! ohohoh omg I get it!!! yeah!!!only one chord bisects the radius!!
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.2
Right, but the radius bisects every chord that it is perpendicular to.
 one year ago

izziewoods Group TitleBest ResponseYou've already chosen the best response.0
yes yes!!! thank you thank you thank you!!! I totally get it now!! you explained it to me really easily!!
 one year ago

mathstudent55 Group TitleBest ResponseYou've already chosen the best response.2
ok, great, you're welcome
 one year ago
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