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RolyPolyBest ResponseYou've already chosen the best response.2
\[y=(x+1)^x\]\[lny = xln(x+1)\]Diff. both sides w.r.t. x
 one year ago

farukkBest ResponseYou've already chosen the best response.0
i have tried but failed in getting answer
 one year ago

RolyPolyBest ResponseYou've already chosen the best response.2
Can you show your work?
 one year ago

farukkBest ResponseYou've already chosen the best response.0
i have a few questions similar to it so explain also
 one year ago

RolyPolyBest ResponseYou've already chosen the best response.2
\[y=(x+1)^x\]\[\ln y=x\ln(x+1)\]Diff. both sides w.r.t. x \[\frac{1}{y} \frac{dy}{dx} = x\frac{d}{dx}(\ln (x+1))+ ln(x+1)\frac{d}{dx}x\] Yes, product rule.
 one year ago

robtobeyBest ResponseYou've already chosen the best response.0
Refer to the attachment.
 one year ago

RolyPolyBest ResponseYou've already chosen the best response.2
\[\frac{1}{y} \frac{dy}{dx} = x\frac{d}{dx}(\ln (x+1))+ ln(x+1)\frac{d}{dx}x\]\[\frac{1}{y} \frac{dy}{dx} = x(\frac{1}{x+1})+ ln(x+1)(1)\]\[\frac{1}{y} \frac{dy}{dx} = (\frac{x}{x+1})+ ln(x+1)\]\[\frac{dy}{dx} = y[(\frac{x}{x+1})+ ln(x+1)]\]Then sub y= (x+1)^x into dy/dx
 one year ago
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