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kgns
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A uniform sphere of mass m and radius r is set free from the top edge of a semicircle halfpipe with radius R. If R > r, what is the timedependent velocity equation v(t) for the sphere in terms of t, m, r, R and g ignoring any effects of friction?
Could anybody help me derive the differential equations?
 one year ago
 one year ago
kgns Group Title
A uniform sphere of mass m and radius r is set free from the top edge of a semicircle halfpipe with radius R. If R > r, what is the timedependent velocity equation v(t) for the sphere in terms of t, m, r, R and g ignoring any effects of friction? Could anybody help me derive the differential equations?
 one year ago
 one year ago

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Mashy Group TitleBest ResponseYou've already chosen the best response.0
i think you can use conservation of energy principle!!
 one year ago

kgns Group TitleBest ResponseYou've already chosen the best response.0
I doubt \[mgh = \frac{ 1 }{ 2 }mv^2\] will get me something in terms of t
 one year ago

MuH4hA Group TitleBest ResponseYou've already chosen the best response.0
No, this won't get you somewhere, because the potential gravitational energy will _not_ be "transformed" into kinetic energy to 100%. There will be rotational energy, too.. you have to take that into account..
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.0
yea.. total kinetic energy = rotational kinectic + translational kinetic.. thats not all that hard cause moment of inertia of the sphere would be known.. and m assuming its without slip!!
 one year ago

kgns Group TitleBest ResponseYou've already chosen the best response.0
If it were an inclined plane, we could stick with \[gtsin \alpha\] with alpha being the angle of inclination. If we consider a semicircle as an infinitesimal sum of inclined planes, we could do \[\int\limits_{0}^{t}gsin \alpha(t) d \alpha\] But it's quite a challenge to derive alpha(t). Not even sure if possible
 one year ago

MuH4hA Group TitleBest ResponseYou've already chosen the best response.0
Shouldn't the acceleration in terms of the angle look like this? dw:1355060534242:dw \[a(\alpha) = g \, \cos(\alpha)\]
 one year ago

kgns Group TitleBest ResponseYou've already chosen the best response.0
Yeah, but since we want velocity in terms of time, we also need to know alpha in terms of t
 one year ago

gleem Group TitleBest ResponseYou've already chosen the best response.0
The problem does not specify that the sphere is rolling i.e. not slipping. Assuming it is rolling makes the problem more difficult especially considering the acceleration is not constant.
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
If you write down the equations, you will end up with a nonlinear differential equation. There is not classical function that will yield v(t). Besides, if you ignore the effects of friction, then the sphere will not rotate and its kinetic energy will purely be given by the motion of its centre of mass.
 one year ago

MuH4hA Group TitleBest ResponseYou've already chosen the best response.0
The problem does not specifiy, but the other option doesn't make any sense for this kind of example.
 one year ago
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