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RolyPoly Group TitleBest ResponseYou've already chosen the best response.1
\[coshy = \frac{e^y+e^{y}}{2}\]\[cosh^2y = (\frac{e^y+e^{y}}{2})^2 = \frac{e^{2y}+e^{2y}+2}{4}\]\[sinhy = \frac{e^ye^{y}}{2}\]\[sinh^2y = (\frac{e^{y}e^{y}}{2})^2 = \frac{e^{2y}+e^{2y}2}{4}\]\[cosh^2ysinh^2y = \frac{e^{2y}+e^{2y}+2}{4}  \frac{e^{2y}+e^{2y}2}{4}=\frac{4}{4}=1\]
 one year ago
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