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RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
\[\int\frac{3cos4x}{2sin2x}dx\]\[=\frac{3}{2}\int\frac{(12sin^22x)}{sin2x}dx\]\[=\frac{3}{2}\int\frac{1}{sin2x}\frac{2sin^22x}{sin2x}dx\]\[=\frac{3}{2}\int(\frac{1}{sin2x}2sin2x)dx\]
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.0
note: \(cos4x =cos^2 2x  sin^2 2x\) \( \frac{3}{2} \int \frac{ \cos^2 2x  \sin^2 2x}{\sin 2x} dx\) =\( \frac{3}{2} [\int \frac{ \cos^2 2x}{\sin 2x} dx \int \sin 2x dx]\) =\( \frac{3}{2} [\int \cos^2 (2x)d(\cos 2x) \int \sin 2x dx]\) do you require further help?
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
@Shadowys The last step is wrong?
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.0
oh right. sorry.
 one year ago

RolyPoly Group TitleBest ResponseYou've already chosen the best response.0
d(cos2x) gives sin2x instead of 1/sin2x
 one year ago
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