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HopelessMathStudent
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What are the foci of the hyperbola given by the equation 16x2  25y2  64x  50y  361 = 0?
 one year ago
 one year ago
HopelessMathStudent Group Title
What are the foci of the hyperbola given by the equation 16x2  25y2  64x  50y  361 = 0?
 one year ago
 one year ago

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helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
complete the squares
 one year ago

HopelessMathStudent Group TitleBest ResponseYou've already chosen the best response.0
How?
 one year ago

HopelessMathStudent Group TitleBest ResponseYou've already chosen the best response.0
(1 ± , 2) (2 ± , 1) (1, 2 ± ) (2, 1 ± )
 one year ago

HopelessMathStudent Group TitleBest ResponseYou've already chosen the best response.0
Its one of these lol Im just not sure which
 one year ago

jishan Group TitleBest ResponseYou've already chosen the best response.0
dw:1355058848205:dw
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
first factor the coeficientes of the squared terms (i rearranged the terms) \[ \large 16x^264x25y^250=361 \] \[ \large 16(x^24x+\qquad)25(y^2+2y+\qquad)=361 \]
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
got this?
 one year ago

HopelessMathStudent Group TitleBest ResponseYou've already chosen the best response.0
Kinda but what are the blank spaces?
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
there's a "y" missing next to the 50.
 one year ago

HopelessMathStudent Group TitleBest ResponseYou've already chosen the best response.0
oh okay
 one year ago

HopelessMathStudent Group TitleBest ResponseYou've already chosen the best response.0
Pretty sure its A or B right?
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
now in each parenthesis there's a blank. u have to write there coeficient of the linear term (no power) halved and then squared \[ \large \color{green}{16}(x^24x+\color{red}{4})\color{orange}{25}(y^2+2y+\color{red}{1})=361 +\color{green}{16}\cdot\color{red}{4}\color{orange}{25}\cdot\color{red}{1} \]
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
got this?
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
http://en.wikipedia.org/wiki/Hyperbola
 one year ago

HopelessMathStudent Group TitleBest ResponseYou've already chosen the best response.0
mhm :)
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
now \[ \large 16(x\color{red}{2})^225(y\color{red}{+1})^2=400 \] \[ \large \frac{16(x\color{red}{2})^2}{400}\frac{25(y(\color{red}{1}))^2}{400}=1 \] \[ \large \frac{(x\color{red}{2})^2}{25}\frac{(y(\color{red}{1}))^2}{16}=1 \]
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
got this?
 one year ago

HopelessMathStudent Group TitleBest ResponseYou've already chosen the best response.0
I see :)
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
now the center of the hyperbola is \[ \large (\color{red}{2},\color{red}{1}) \]
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
is it a horizontal or vertical hyperbola? how can u tell?
 one year ago

HopelessMathStudent Group TitleBest ResponseYou've already chosen the best response.0
horizontal
 one year ago

HopelessMathStudent Group TitleBest ResponseYou've already chosen the best response.0
the format of the equation.
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
look at the denominators which is larger? under x? or under y?
 one year ago

HopelessMathStudent Group TitleBest ResponseYou've already chosen the best response.0
x.....
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
yes. this tells u the hyperbola is horizontal
 one year ago

HopelessMathStudent Group TitleBest ResponseYou've already chosen the best response.0
I said it was horizontal. Is it B?
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
what is the length of the semimayor axis?
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
it HAS to. do u know why?
 one year ago

HopelessMathStudent Group TitleBest ResponseYou've already chosen the best response.0
because the formula is formatted (h±a,k) for horizontal and that fits? lol
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
yes. very clever. u were looking for the foci not the vertices, though.
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
did u understand?
 one year ago

HopelessMathStudent Group TitleBest ResponseYou've already chosen the best response.0
do it is B? :) and yeah pretty much lol
 one year ago

HopelessMathStudent Group TitleBest ResponseYou've already chosen the best response.0
so*
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.0
i hope so.
 one year ago
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